# A Level Maths Integration Edexcel Challenge Question Help

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#1
Hi, so I'm revising for my after, easter maths mock and stuck on this challenge question, firstly how would you approach this question with the 2√x I understand how to do the second bracket just not sure about the 2√x in the first bracket,
Last edited by liamlarner2020; 3 months ago
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3 months ago
#2
this is differential equations so would you use integration by parts and integrate each bracket 2x^0.5 isnt a hard integration
I may be completely wrong

also what chapter is it so i can try it
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#3
(Original post by moriyanu)
this is differential equations so would you use integration by parts and integrate each bracket 2x^0.5 isnt a hard integration
I may be completely wrong

also what chapter is it so i can try it
Edexcel A Level Maths Pure Year 1 Textbook Chapter 13 Page 290 at the very top just above 13.2 section, quite bad if it is integration by parts since in textbook order i have not met that yet
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3 months ago
#4
(Original post by liamlarner2020)
Edexcel A Level Maths Pure Year 1 Textbook Chapter 13 Page 290 at the very top just above 13.2 section, quite bad if it is integration by parts since in textbook order i have not met that yet
ohhhh its AS ignore what I said.
Expand it and integrate that's what they want
remember to multiply x to the power of something you just add the powers and it may be easier turning the root into 0.5 or 1/2
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3 months ago
#5
(Original post by liamlarner2020)
Hi, so I'm revising for my after, easter maths mock and stuck on this challenge question, firstly how would you approach this question with the 2√x I understand how to do the second bracket just not sure about the 2√x in the first bracket,
It looks worse than it is! Just remember that , multiply out all the brackets, use indices rules to combine terms and then integrate each term.
Last edited by davros; 3 months ago
1
3 months ago
#6
(Original post by davros)
It looks worse than it is! Just remember that , multiply out all the brackets, use indices rules to combine terms and then differentiate each term.
It’s integration because your trying to find y
Dy/dx given so to get to expression of y in terms of x you integrate both sides
It’s like introducing differential equations
0
3 months ago
#7
(Original post by moriyanu)
It’s integration because your trying to find y
Dy/dx given so to get to expression of y in terms of x you integrate both sides
It’s like introducing differential equations
Edited now to correct.
Method is still basically the same: rewrite in index notation, multiply out, integrate as normal.
Last edited by davros; 3 months ago
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