as chem combustion question help??Watch
CH4(g) +2O2(G) --> CO2(g) +2H20 (L) ENTHALPY CHANGE= -890kjmol-1
CO(g) + 1/2 O2 (g) ---> CO2(g) ENTHALPY CHANGE= -284kjmol-1
C(s)+O2(g)---> CO2(g) ENTHALPY CHANGE= -393kjmol-1
H2 (g) + 1/2 O2 (g) ----> H20 (l) ENTHALPY CHANGE= -286kjmol-1
1) The enthalpy of formation of methane
2)The enthalpy of formation of carbon monoxide
3) the enthalpy change when methane is brunt in limited oxygen to form carbon monoxide and water.
I need help with Q3. I wrote the formula so it will be:
CH4(g) +1.5O2(G)----> co2(g) + 2H20 (L)
Bc this formula is the combustion of methane does that mean we set up a cycle (with formation) so the formula underneath when drawing the cycle would be C(s) +1.5O2 +2H2
Since we set up a formation cycle its P-R so i get 606 kj/mol but the answers say -606. Pls can someone help with this??