# Maths

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I need help with this question:

20) There are only red sweets and yellow sweets in a bag.

There are n red sweets in the bag.

There are 8 yellow sweets in the bag.

Sajid is going to take at random a sweet from the bag and eat it.

He says that the probability that the sweet will be red is

7/10(a) Show why the probability cannot be

7/10

20) There are only red sweets and yellow sweets in a bag.

There are n red sweets in the bag.

There are 8 yellow sweets in the bag.

Sajid is going to take at random a sweet from the bag and eat it.

He says that the probability that the sweet will be red is

7/10(a) Show why the probability cannot be

7/10

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#2

(Original post by

I need help with this question:

20) There are only red sweets and yellow sweets in a bag.

There are n red sweets in the bag.

There are 8 yellow sweets in the bag.

Sajid is going to take at random a sweet from the bag and eat it.

He says that the probability that the sweet will be red is

7/10(a) Show why the probability cannot be

7/10

**raidas0001**)I need help with this question:

20) There are only red sweets and yellow sweets in a bag.

There are n red sweets in the bag.

There are 8 yellow sweets in the bag.

Sajid is going to take at random a sweet from the bag and eat it.

He says that the probability that the sweet will be red is

7/10(a) Show why the probability cannot be

7/10

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#3

although this question involves sweets, it should not really be in the Food and Drink forum

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#4

**raidas0001**)

I need help with this question:

20) There are only red sweets and yellow sweets in a bag.

There are n red sweets in the bag.

There are 8 yellow sweets in the bag.

Sajid is going to take at random a sweet from the bag and eat it.

He says that the probability that the sweet will be red is

7/10(a) Show why the probability cannot be

7/10

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#6

(Original post by

2/10 ,because 8/10 + 2/10 = 10/10 ,since the 10 in the denominator reveals the number of candies in the bag as a whole

**lucydales**)2/10 ,because 8/10 + 2/10 = 10/10 ,since the 10 in the denominator reveals the number of candies in the bag as a whole

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(Original post by

What are your thoughts?

**Muttley79**)What are your thoughts?

10n=7n+56

3n=56

n=18.66666666666666

if the probability of getting red is 7/10 then there is a decimal number of red sweets and u can't have 0.6666666667 of a sweet.

i am not sure if i'm correct

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#8

(Original post by

n/(n+8)=7/10

10n=7n+56

3n=56

n=18.66666666666666

if the probability of getting red is 7/10 then there is a decimal number of red sweets and u can't have 0.6666666667 of a sweet.

i am not sure if i'm correct

**raidas0001**)n/(n+8)=7/10

10n=7n+56

3n=56

n=18.66666666666666

if the probability of getting red is 7/10 then there is a decimal number of red sweets and u can't have 0.6666666667 of a sweet.

i am not sure if i'm correct

I'd reword it slightly, since in general all numbers are decimal (it just means base 10).

If the probabilty of getting a red is 7/10, then there must be 18 2/3 sweets. Since the number of sweets must be a whole number it follows you can't get a probability of getting a red being 7/10 .

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#9

(Original post by

What are your thoughts?

**Muttley79**)What are your thoughts?

After Sajid has taken the first sweet from the bag and eaten it, he is going to take at random a second sweet from the bag. Given that the probability that both the sweets he takes will be red is 3/5.

Work out the number of red sweets in the bag.

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#10

**raidas0001**)

I need help with this question:

20) There are only red sweets and yellow sweets in a bag.

There are n red sweets in the bag.

There are 8 yellow sweets in the bag.

Sajid is going to take at random a sweet from the bag and eat it.

He says that the probability that the sweet will be red is

7/10(a) Show why the probability cannot be

7/10

If the probability of a red sweet is 7/10 then the probability of a yellow sweet is 3/10 meaning that the number of total sweets will be 8*10/3 which is 26 3/4. This doesn't make sense as mentioned before, non-whole numbers don't make sense.

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#11

**raidas0001**)

I need help with this question:

20) There are only red sweets and yellow sweets in a bag.

There are n red sweets in the bag.

There are 8 yellow sweets in the bag.

Sajid is going to take at random a sweet from the bag and eat it.

He says that the probability that the sweet will be red is

7/10(a) Show why the probability cannot be

7/10

After Sajid has taken the first sweet from the bag and eaten it, he is going to take at random a second sweet from the bag. Given that the probability that both the sweets he takes will be red is 3/5.

Work out the number of red sweets in the bag.

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#12

Nope, you need an algebraic explanation for that create a simple expression from teh info given to you and you will realise you just do not get a whol enumber

Last edited by Fiaraziqbal; 2 months ago

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