Go to first unread
Back
to top
Forces question pls help
Watch this thread
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#1
A wooden block is stationary on a ramp.
The diagram isn’t drawn to scale.
The block has weight W. The normal contact force on the block is N. The frictional force F on the block is shown on the diagram. Which triangle of forces diagram is correct?
A
B
C
Or D
Can someone please help me with this :/
The diagram isn’t drawn to scale.
The block has weight W. The normal contact force on the block is N. The frictional force F on the block is shown on the diagram. Which triangle of forces diagram is correct?
A
B
C
Or D
Can someone please help me with this :/
0
reply
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#2
(Original post by Sonnysingh22)
A wooden block is stationary on a ramp.
The diagram isn’t drawn to scale.
The block has weight W. The normal contact force on the block is N. The frictional force F on the block is shown on the diagram. Which triangle of forces diagram is correct?
A
B
C
Or D
Can someone please help me with this :/
A wooden block is stationary on a ramp.
The diagram isn’t drawn to scale.
The block has weight W. The normal contact force on the block is N. The frictional force F on the block is shown on the diagram. Which triangle of forces diagram is correct?
A
B
C
Or D
Can someone please help me with this :/
0
reply
mqb2766
Badges:
19
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#3
Report
#3
You seem to be posting a lot of multichoice test questions?
What do you understand about the question?
What do you understand about the question?
1
reply
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#4
(Original post by mqb2766)
You seem to be posting a lot of multichoice test questions?
What do you understand about the question?
You seem to be posting a lot of multichoice test questions?
What do you understand about the question?
I understand that weight is acting down and the normal contact force is acting to the left so I thought the answer is B but I’m not sure
0
reply
mqb2766
Badges:
19
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#5
Report
#5
(Original post by Sonnysingh22)
I found a pack of multiple choice questions online and I’m doing them as revision but I don’t know how to do the ones I’ve posted that’s why I have.
I understand that weight is acting down and the normal contact force is acting to the left so I thought the answer is B but I’m not sure
I found a pack of multiple choice questions online and I’m doing them as revision but I don’t know how to do the ones I’ve posted that’s why I have.
I understand that weight is acting down and the normal contact force is acting to the left so I thought the answer is B but I’m not sure
Where did you find them, Id be interested in seeing them.
0
reply
djarlin
Badges:
6
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#6
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#7
(Original post by mqb2766)
If it's for your own revision, why not stop posting new questions and think/read about the topic underpinning each question. You'll learn more that way, which I presume is your aim of you're just randomly doing online questions.
Where did you find them, Id be interested in seeing them.
If it's for your own revision, why not stop posting new questions and think/read about the topic underpinning each question. You'll learn more that way, which I presume is your aim of you're just randomly doing online questions.
Where did you find them, Id be interested in seeing them.
I’ll find them again and attach the link.
0
reply
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#8
djarlin
Badges:
6
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#9
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#10
0
reply
djarlin
Badges:
6
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#11
Report
#11
(Original post by Sonnysingh22)
Thank you so much, I appreciate it!!
Thank you so much, I appreciate it!!
0
reply
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#12
(Original post by djarlin)
you're welcome! but there was a little mistake in where i put the angle, its actually supposed to be opposite mg sin theta 😅 the rest is correct once you fix that. and im happy to help anytime, mcqs are tough man.![Name: 20210324_135148-compressed.jpg.jpeg
Views: 39
Size: 15.5 KB]()
you're welcome! but there was a little mistake in where i put the angle, its actually supposed to be opposite mg sin theta 😅 the rest is correct once you fix that. and im happy to help anytime, mcqs are tough man.
0
reply
djarlin
Badges:
6
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#13
Report
#13
(Original post by Sonnysingh22)
Ah I know what you’re saying bro they’re so hard, they take me so long to do so thank you for the help. I’ve done these questions I just don’t know if I’m right if I send you a few can you let me know what you think?
Ah I know what you’re saying bro they’re so hard, they take me so long to do so thank you for the help. I’ve done these questions I just don’t know if I’m right if I send you a few can you let me know what you think?
0
reply
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#14
(Original post by djarlin)
yeah ofcourse! if u take maths they'll be easier but without is totally doable too.
yeah ofcourse! if u take maths they'll be easier but without is totally doable too.
A tennis ball is hit with a racket. The force applied by the racket of the ball is F. The ball has a vertical path through the air.
Which statement is correct when the ball is at its maximum height?
A The ball has downward acceleration
B The force acting on the ball is F
C The ball experiences greatest drag
D The weight of the ball is equal to the drag
I’m not sure about this one but I was thinking A?
Last edited by Sonnysingh22; 1 year ago
0
reply
djarlin
Badges:
6
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#15
Report
#15
(Original post by Sonnysingh22)
I don’t do maths so it makes it a bit harder :/
A tennis ball is hit with a racket. The force applied by the racket of the ball is F. The ball has a vertical path through the air.
Which statement is correct when the ball is at its maximum height?
A The ball has downward acceleration
B The force acting on the ball is F
C The ball experiences greatest drag
D The weight of the ball is equal to the drag
I’m not sure about this one but I was thinking A?
I don’t do maths so it makes it a bit harder :/
A tennis ball is hit with a racket. The force applied by the racket of the ball is F. The ball has a vertical path through the air.
Which statement is correct when the ball is at its maximum height?
A The ball has downward acceleration
B The force acting on the ball is F
C The ball experiences greatest drag
D The weight of the ball is equal to the drag
I’m not sure about this one but I was thinking A?
0
reply
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#16
(Original post by djarlin)
omg hate these kind of vague qs. but on the other hand A sounds correct!!! at max height acceleration is zero bc speed/ velocity is zero which is because net force is zero. the only force acting throughout motion is gravity which causes the acceleration and deceleration and momentary stop ( max height) of the ball before it falls back down. this is a terminal velocity concept question btw, and a good one that you can add to your notes
omg hate these kind of vague qs. but on the other hand A sounds correct!!! at max height acceleration is zero bc speed/ velocity is zero which is because net force is zero. the only force acting throughout motion is gravity which causes the acceleration and deceleration and momentary stop ( max height) of the ball before it falls back down. this is a terminal velocity concept question btw, and a good one that you can add to your notes
The oscillator is forced to oscillate at different frequencies. The graph of amplitude A against driving frequency f for the oscillator is shown.
The damping on the oscillator is now decreased. Which of the following statements is/are correct?
1 the amplitude of the oscillations at any frequency decreases.
2 the maximum amplitude occurs at a lower frequency.
3 the peak on the graph becomes thinner.
Idk about this one. I think it is C but not really sure ?
0
reply
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#17
(Original post by djarlin)
omg hate these kind of vague qs. but on the other hand A sounds correct!!! at max height acceleration is zero bc speed/ velocity is zero which is because net force is zero. the only force acting throughout motion is gravity which causes the acceleration and deceleration and momentary stop ( max height) of the ball before it falls back down. this is a terminal velocity concept question btw, and a good one that you can add to your notes
omg hate these kind of vague qs. but on the other hand A sounds correct!!! at max height acceleration is zero bc speed/ velocity is zero which is because net force is zero. the only force acting throughout motion is gravity which causes the acceleration and deceleration and momentary stop ( max height) of the ball before it falls back down. this is a terminal velocity concept question btw, and a good one that you can add to your notes
the gravitational force between two point mass objects X and Y is F1.
The mass of X increases and the distance between X and Y is halved.
which statement about the new gravitational force F2 between these two objects is correct?
a 0 < F2 < 0.25F1
b F2 > 4F1
c F2 = F1
d 2F1 < F2 < 4F1
for this I guessed A but I don’t think that’s right
all these questions I have tried to work them out but these were the ones I found hard, I really hate multiple choice
0
reply
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#18
(Original post by djarlin)
omg hate these kind of vague qs. but on the other hand A sounds correct!!! at max height acceleration is zero bc speed/ velocity is zero which is because net force is zero. the only force acting throughout motion is gravity which causes the acceleration and deceleration and momentary stop ( max height) of the ball before it falls back down. this is a terminal velocity concept question btw, and a good one that you can add to your notes
omg hate these kind of vague qs. but on the other hand A sounds correct!!! at max height acceleration is zero bc speed/ velocity is zero which is because net force is zero. the only force acting throughout motion is gravity which causes the acceleration and deceleration and momentary stop ( max height) of the ball before it falls back down. this is a terminal velocity concept question btw, and a good one that you can add to your notes
The electron makes the transition shown by the arrow. What is the wavelength of the photon emitted?
For this my working:
E = hc/landa
(-1.36 x 10^-19) + (-5.44 x 10^-19) = -6.8 x 10^-19
-6.8 x 10^-19 = 6.63 x 10^-34 x 3 x 10^8 / landa
Wavelength = 1.989 x 10^-25 / -6.8 x 10^-19 = -2.925 x 10^-7
That’s what I got
But the multiple choice question answers are:
366nm
1460nm
293nm
And 488nm
So I’m not sure if I’ve gone wrong or if I was completely wrong
0
reply
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#19
(Original post by djarlin)
omg hate these kind of vague qs. but on the other hand A sounds correct!!! at max height acceleration is zero bc speed/ velocity is zero which is because net force is zero. the only force acting throughout motion is gravity which causes the acceleration and deceleration and momentary stop ( max height) of the ball before it falls back down. this is a terminal velocity concept question btw, and a good one that you can add to your notes
omg hate these kind of vague qs. but on the other hand A sounds correct!!! at max height acceleration is zero bc speed/ velocity is zero which is because net force is zero. the only force acting throughout motion is gravity which causes the acceleration and deceleration and momentary stop ( max height) of the ball before it falls back down. this is a terminal velocity concept question btw, and a good one that you can add to your notes
What is the value, written to 2 significant figures in s-1?
For this I think it is B
0
reply
Sonnysingh22
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#20
(Original post by djarlin)
omg hate these kind of vague qs. but on the other hand A sounds correct!!! at max height acceleration is zero bc speed/ velocity is zero which is because net force is zero. the only force acting throughout motion is gravity which causes the acceleration and deceleration and momentary stop ( max height) of the ball before it falls back down. this is a terminal velocity concept question btw, and a good one that you can add to your notes
omg hate these kind of vague qs. but on the other hand A sounds correct!!! at max height acceleration is zero bc speed/ velocity is zero which is because net force is zero. the only force acting throughout motion is gravity which causes the acceleration and deceleration and momentary stop ( max height) of the ball before it falls back down. this is a terminal velocity concept question btw, and a good one that you can add to your notes
Which object travels the greatest distance between t= 0 and t = T?
I put A because the gradient is the steepest but I’m not sure again
0
reply
X
Quick Reply
