Qxi.xli
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x= root (y+1)

my textbook simplified that to x= root y + 1

i was under the impression that you're not allowed to do that?
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HoldThisL
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1^2 = 1

therefore root(1) = 1 also

so you can do it because:

root(y + 1) = root(y) + root(1)
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Driving_Mad
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The square root of 1 is 1, so you can.
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mdvmxnd
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Sounds incorrect, e.g. if y = 3, then x = sqrt(y + 1) = sqrt(4) = 2, but that rule would assume sqrt(3) + 1 would also equal 2, which it doesn't. Works when y = 0 though.
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mathcool
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(Original post by Qxi.xli)
x= root (y+1)

my textbook simplified that to x= root y + 1

i was under the impression that you're not allowed to do that?
You are correct that it is not allowed.

So, how can it verified?

x = root(y+1)

x squared = y + 1

when Z = root (P) + 1

Z squared = P + (2 * 1 * root (P)) + 1

(in the x, y form, x squared = y + (2 * 1 * root (y)) + 1)

Obviously, two completely different meaning.
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Muttley79
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(Original post by Qxi.xli)
x= root (y+1)

my textbook simplified that to x= root y + 1

i was under the impression that you're not allowed to do that?
Might you have gone wrong because they aren't the same
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Muttley79
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(Original post by Driving_Mad)
The square root of 1 is 1, so you can.
No, it's wrong
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Qxi.xli
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(Original post by mathcool)
You are correct that it is not allowed.

So, how can it verified?

x = root(y+1)

x squared = y + 1

when Z = root (P) + 1

Z squared = P + (2 * 1 * root (P)) + 1

(in the x, y form, x squared = y + (2 * 1 * root (y)) + 1)

Obviously, two completely different meaning.
thanks so much
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davros
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#9
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(Original post by Qxi.xli)
x= root (y+1)

my textbook simplified that to x= root y + 1

i was under the impression that you're not allowed to do that?
Can you upload a picture o that section of your textbook where they do this? (What you've posted is definitely incorrect, but it's possible that they meant to do something else in the book)
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