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Incline planes
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r7kytt
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#1
mqb2766
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#2
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#2
Look at the"triangle" where the ladder is resting on the drum at P. The horizontal component is Nsin(35)
Last edited by mqb2766; 1 year ago
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r7kytt
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#3
(Original post by mqb2766)
Look at the"triangle" where the ladder is resting on the drum at P. The horizontal component is Nsin(35)
Look at the"triangle" where the ladder is resting on the drum at P. The horizontal component is Nsin(35)
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mqb2766
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r7kytt
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#5
(Original post by mqb2766)
Resolve N.
Resolve N.
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mqb2766
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#6
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#6
(Original post by r7kytt)
Resolving for N, you take F from the ground and then the resultant forces, but Nsin35 isn’t the horizontal component...
Resolving for N, you take F from the ground and then the resultant forces, but Nsin35 isn’t the horizontal component...
N has a horizontal component so draw a right angled triangle (one vertex is P) to resolve things as usual. They've already given you an angle and two of the sides.
Last edited by mqb2766; 1 year ago
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r7kytt
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#7
(Original post by mqb2766)
? F has nothing g to do with resolving N.
N has a horizontal component draw a right angled triangle (one vertex is P) to resolve things. They've already given you an angle and two of the sides.
? F has nothing g to do with resolving N.
N has a horizontal component draw a right angled triangle (one vertex is P) to resolve things. They've already given you an angle and two of the sides.
Then?
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mqb2766
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#8
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#8
Last edited by mqb2766; 1 year ago
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r7kytt
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#9
(Original post by mqb2766)
Because the (two) forces are in equilibrium (horizontally).
Because the (two) forces are in equilibrium (horizontally).
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r7kytt
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#10
I think the confusion is in the diagram, I think I get it now but the diagram is at an angle. Thank you
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r7kytt
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#11
mqb2766
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#12
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#12
(Original post by r7kytt)
Sorry, I still can’t see it. I was under the impression that resolving horizontally had to go in the opposite direction and vice versa to vertically. I’m very confused, I see what you mean by Nsin35 right angle triangle but not sure why they would be equal or rather why it’s took as a horizontal component
Sorry, I still can’t see it. I was under the impression that resolving horizontally had to go in the opposite direction and vice versa to vertically. I’m very confused, I see what you mean by Nsin35 right angle triangle but not sure why they would be equal or rather why it’s took as a horizontal component
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r7kytt
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#13
(Original post by mqb2766)
Why not draw your own diagram, concentrating on the horizontal forces and upload it together with the force equation that describes horizontal equilibrium. It's easier to help if I can understand what you think.
Why not draw your own diagram, concentrating on the horizontal forces and upload it together with the force equation that describes horizontal equilibrium. It's easier to help if I can understand what you think.
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davros
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#14
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#14
(Original post by r7kytt)
I get it now, the confusion was the diagram. It’s north, not north east. It looked north east, I think I’m just tired
I get it now, the confusion was the diagram. It’s north, not north east. It looked north east, I think I’m just tired
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r7kytt
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#15
(Original post by davros)
What's north? The normal reaction N at P is normal to the ladder and the ladder is inclined at an angle to the horizontal, so N certainly isn't pointing north. The diagram looks OK to me
What's north? The normal reaction N at P is normal to the ladder and the ladder is inclined at an angle to the horizontal, so N certainly isn't pointing north. The diagram looks OK to me
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mqb2766
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#16
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#16
(Original post by r7kytt)
What??! So why would it be Nsin35???
What??! So why would it be Nsin35???
Please try your own solution and upload your working.
Last edited by mqb2766; 1 year ago
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davros
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#17
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#17
(Original post by r7kytt)
What??! So why would it be Nsin35???
What??! So why would it be Nsin35???
It might help to draw a horizontal line through P so that you can see what the angles are. Since the ladder is at an angle 35 degrees to the ground, a horizontal line through P makes an angle 35 degrees with the ladder (alternate angles). Given that the force N is normal to the ladder at contact point P, you should now be able to resolve N into its horizontal and vertical components.
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r7kytt
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#18
But Nsin35 is not horizontal? That’s at a slant??????????
![Name: D82A4ACF-DA26-40B0-8C8B-5305EE4F54E9.jpg.jpeg
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If you had a ladder, for example
![Name: 3A84B7C7-DAF7-4931-9250-41C91D0AD906.jpg.jpeg
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Both forces are horizontal so you can equal them, so why isn’t Nsin35 horizontal but it equals force on the ground ?
If you had a ladder, for example
Both forces are horizontal so you can equal them, so why isn’t Nsin35 horizontal but it equals force on the ground ?
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davros
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r7kytt
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#20
I see it now thank you!
You confused me because I got it last night, it’s because I drew the triangle wrong lmao
You confused me because I got it last night, it’s because I drew the triangle wrong lmao
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