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Need help with Trigonometry

Hey guys! Can someone solve this question for me?

Given that sin(x - 60) = 3cos (x - 45), find the exact value of tan x
Original post by fmkch03
Hey guys! Can someone solve this question for me?

Given that sin(x - 60) = 3cos (x - 45), find the exact value of tan x


sin(A±B)=sinAcosB±cosAsinB\sin(A \pm B) = \sin A \cos B \pm \cos A \sin B

cos(A±B)=...\cos( A \pm B)= ...
Reply 2
Original post by Plücker
sin(A±B)=sinAcosB±cosAsinB\sin(A \pm B) = \sin A \cos B \pm \cos A \sin B

cos(A±B)=...\cos( A \pm B)= ...

Could you tell me the necessary steps to solve this question?
Original post by fmkch03
Could you tell me the necessary steps to solve this question?

Use sin(A-B)=sinAcosB - cosAsinB to write an expression for sin(x-60). Post what you get.
Reply 4
Original post by fmkch03
Could you tell me the necessary steps to solve this question?

CAn you use the rules given above to expand sin(x - 60) and cos(x - 45)? Remember that sin 60, cos 60, sin 45 and cos 45 are standard values that you should know.

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