TjaidN
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#1
Report Thread starter 1 year ago
#1
Radical reactions are responsible for the catalysed breakdown of the ozone layer.

The overall equation is shown below:

2O3→3O2
ΔrH=-284kJmol-1
The molar gas volume in the ozone layer is approximately 2.5m3
mol-1
What is the energy release, in kJ, during the breakdown of 1.0m
3
of ozone in the ozone layer?
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rxda
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#2
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#2
Have you figured it out I'm curious lol
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rxda
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#3
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#3
I'm thinking maybe you would scale it out if 2.5m3 is 284kj maybe to get in 1m3 its 284/2.5
I doubt that's right lol
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TjaidN
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#4
Report Thread starter 1 year ago
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(Original post by rxda)
Have you figured it out I'm curious lol
I’m thinking because u have the gas constant as 2.5 instead of normally 24 and u already have the concentration and volume, you do 1/2.5 x -284?
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MDA 5
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#5
Report 5 months ago
#5
From what I think, because the molar gas volume is 2.5m3 per mole and there are 2 moles of ozone being broken down, if you do 2 times 2.5, this gives 5. So instead of 284 divided by 2.5 it would be 284 divided by 5 because 2 moles of ozone is broken down and 2.5m3mol-1 only applies to one mole.
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