r.maliak
Badges: 10
Rep:
?
#1
Report Thread starter 3 weeks ago
#1
Name:  Screenshot (82).png
Views: 6
Size:  5.2 KB
is it sinx(7/cosx - 8) = 0
so sin(4a +199) = 0 and
cos(4a+199) = 7/8
the answer is 33 and solving the 2 dont give 33?
Last edited by r.maliak; 3 weeks ago
0
reply
mqb2766
Badges: 19
Rep:
?
#2
Report 3 weeks ago
#2
(Original post by r.maliak)
Name:  Screenshot (82).png
Views: 6
Size:  5.2 KB
is it sinx(7/cosx - 8) = 0
so sin(4a +199) = 0 and
cos(4a+199) = 7/8
the answer is 33 and solving the 2 dont give 33?
How did you solve the asin and acos parts?
0
reply
r.maliak
Badges: 10
Rep:
?
#3
Report Thread starter 3 weeks ago
#3
(Original post by mqb2766)
How did you solve the asin and acos parts?
sin(4a+199) = 0
sin-1(0) = 0
4a+199 = 0
a = -199/3
0
reply
mqb2766
Badges: 19
Rep:
?
#4
Report 3 weeks ago
#4
(Original post by r.maliak)
sin(4a+199) = 0
sin-1(0) = 0
4a+199 = 0
a = -199/3
There are multiple solutions for
sin(*) = 0
The +199 is a hint that the obvious one, may not be the correct one.

Similarly for cos(*) solutions
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

Should 'Mental health support' be included on league tables?

Yes (191)
74.9%
No (64)
25.1%

Watched Threads

View All