cm49919
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A level further maths.
Can't solve the following question
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cm49919
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RDKGames
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(Original post by cm49919)
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What have you tried?
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cm49919
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(Original post by RDKGames)
What have you tried?
I have proved that it's true for n=1 and assume it's true for n=k. Then I let n=k+1, not sure if it's correct or not.
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RDKGames
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(Original post by cm49919)
I have proved that it's true for n=1 and assume it's true for n=k. Then I let n=k+1, not sure if it's correct or not.
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It reads a bit awkward but you get the jist of it.

Point here is to be clear. You are assuming the result to be true for all k\leq n

then u_{k+1} = 5u_{k} - 6u_{k-1}

and sub in the hypotheses for u_k,u_{k-1} before simplifying in the same way you did.
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cm49919
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(Original post by RDKGames)
It reads a bit awkward but you get the jist of it.

Point here is to be clear. You are assuming the result to be true for all k\leq n

then u_{k+1} = 5u_{k} - 6u_{k-1}

and sub in the hypotheses for u_k,u_{k-1} before simplifying in the same way you did.
Thank you so much
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ghostwalker
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(Original post by cm49919)
Thank you so much
Note: Starting with n=1, the formula defines u_3.

As such your base case needs to be for both u_1 and u_2
Last edited by ghostwalker; 2 weeks ago
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