Yazomi
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Is there an error on the mark scheme?
For the answer iv)
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ghostwalker
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(Original post by Yazomi)
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Is there an error on the mark scheme?
For the answer iv)
No.

Compare q(x) with g(x) with regard to the constant - it's gone from +4 to +1; change is -3 in the y-direction.
Last edited by ghostwalker; 2 weeks ago
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RDKGames
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(Original post by Yazomi)
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Is there an error on the mark scheme?
For the answer iv)
Nope.

If q(x)=x^2+4 then q(x-3)-3 = (x-3)^2 + 1 which is g(x)
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Yazomi
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(Original post by ghostwalker)
No.

Compare q(x) with g(x) with regard to the constant - it's gone from +4 to +1; change is -3 in the y-direction.
Wait why is q(x) being compared instead of f(x)?
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Yazomi
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(Original post by RDKGames)
Nope.

If q(x)=x^2+4 then q(x-3)-3 = (x-3)^2 + 1 which is g(x)
I thought the question was asking for a comparison of f(x) rather than q(x)?
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RDKGames
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(Original post by Yazomi)
I thought the question was asking for a comparison of f(x) rather than q(x)?
Not sure what you mean.

You want to solve f(x)=g(x) but using the solution to p(x)=q(x). So you rewrite f,g in terms of p,q.
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ghostwalker
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(Original post by Yazomi)
Wait why is q(x) being compared instead of f(x)?
You compare q(x) with g(x) to find how q(x) has been transformed.

You compare p(x) with f(x) to find how p(x) has been transformed.

And it turns out they've both been transformed by the same amount (3,-3)
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Yazomi
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(Original post by ghostwalker)
You compare q(x) with g(x) to find how q(x) has been transformed.

You compare p(x) with f(x) to find how p(x) has been transformed.

And it turns out they've both been transformed by the same amount (3,-3)
Wait how do you know which ones to compare is it just because q(x) and g(x) highest power is x^3

And p(x) and f(x) highest power is x^2?

(Original post by RDKGames)
Not sure what you mean.

You want to solve f(x)=g(x) but using the solution to p(x)=q(x). So you rewrite f,g in terms of p,q.
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RDKGames
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(Original post by Yazomi)
Wait how do you know which ones to compare is it just because q(x) and g(x) highest power is x^3

And p(x) and f(x) highest power is x^2?
Yes . Can’t compare a cubic to a quadratic ... this is a nonlinear transformation.
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Yazomi
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(Original post by RDKGames)
Yes . Can’t compare a cubic to a quadratic ... this is a nonlinear transformation.
Ahhh this makes sense now thank you so much
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ghostwalker
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(Original post by Yazomi)
Ahhh this makes sense now thank you so much
To sum up:

p and q are two functions that intersect at a certain point.

p is transformed to f, and q is transformed to g

By comparing p and f we find what the transformation is from one to the other.
By comparing q and g we find what that transformation is.

They are the same; both graphs have been shifted in an identical manner, and so their point of intersection will have been shifted in the same manner.
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the bear
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the intersection of p(x) and q(x) is at (2,8)

the intersection of p(x-3)-3 and q(x-3)-3 will be the point (2,8) with a translation of 3 right and 3 down.
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