# pleaseee help me with this physics question

Watch
#1
figure seven: two people playing ice hockey.
player A: mass = 78kg velocity = +7.5 m/s
player B: mass = 91 kg velocity = -5.5 m/s

question:
immediately after the collision the two players move together to the right. calculate the velocity of the two players immediately after the collision.
0
1 month ago
#2
How much do you know about momentum
0
1 month ago
#3
m1u1 + m2u2 = m1v1 + m2v2

take 1 to be player A and 2 to be player B

for final momentum (v) their masses will be combined so add them .. (169v) should be on the r.h.side

585 + (-500.5) = 169v
and solve for v
2
#4
(Original post by 90 cent)
m1u1 + m2u2 = m1v1 + m2v2

take 1 to be player A and 2 to be player B

for final momentum (v) their masses will be combined so add them .. (169v) should be on the r.h.side

585 + (-500.5) = 169v
and solve for v
thank u so much
1
1 month ago
#5
What paper is this on? Because I also did this but I'm struggling to find the mark scheme.Thank you
2
1 month ago
#6
(Original post by meli77)
thank u so much

So what would v be ???
And what equation was used
1
4 weeks ago
#7
momentum= mass x velocity
And I got 0.5m/s for v but it doesn't sound right
0
3 weeks ago
#8
(Original post by meli77)
thank u so much
1
2 weeks ago
#9
(Original post by meli77)
figure seven: two people playing ice hockey.
player A: mass = 78kg velocity = +7.5 m/s
player B: mass = 91 kg velocity = -5.5 m/s

question:
immediately after the collision the two players move together to the right. calculate the velocity of the two players immediately after the collision.
0
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