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#1
Someone helps me to integrate this funtion pls.
3(1+t^2) / ( 2(3t+1)^2 +6 )
Last edited by Vropropopop; 2 weeks ago
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2 weeks ago
#2
(Original post by Vropropopop)
Someone helps me to integrate this funtion pls.
3(1+t^2) / ( 2(3t+1)^2 +6 )
I'd try to factor out as much of the numbers as you can so it makes life easy on yourself e.g. 3/2 can easily be taken out due to the numerator and denominator. Then you are left with (1+t^2)/((3t+1)^2+3) to integrate.
Multiply out the factor where necessary.

For the integral, you are essentially looking at an intergration by parts, unfortunately, so you will need to assign one part of the equation as U and the other dv/dx.
You will likely end up using the chain rule for parts of the integration (e.g. U or V), since it doesn't look straightforward.
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2 weeks ago
#3
(Original post by Vropropopop)
Someone helps me to integrate this funtion pls.
3(1+t^2) / ( 2(3t+1)^2 +6 )
It looks very messy tbh. Is this an actual question you have been asked to solve, or have you ended up with this after manipulating some other integral?
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2 weeks ago
#4
(Original post by davros)
It looks very messy tbh. Is this an actual question you have been asked to solve, or have you ended up with this after manipulating some other integral?
The question, which is incorrectly stated, is from a locked paper.
2
2 weeks ago
#5
(Original post by Plücker)
The question, which is incorrectly stated, is from a locked paper.
Ah, I see
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2 weeks ago
#6
Apologies to the OP.

Although it's from a 2020 paper the question has been released here: https://qualifications.pearson.com/e...s-for-students

The question itself is here. http://prntscr.com/11v91rf
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