M1 after the exam discussion Watch

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Womble548
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#61
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#61
(Original post by faa)
what did you all get for the question part d where they said that the impulse was 2.4Ns ? You had to find the time taken for the object to hit a wall and roll back............?
I got 3.06, some people got 3.07. I think it depends when/if you rounded the speed of the particle or kept it at 24-sqrt220
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!Laxy!
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#62
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(Original post by !Laxy!)
I know this isnt about this exam, but does anyone know what the raw mark needed for an A in the June 2004 M1 paper was?
is that a no?
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ThugzMansion7
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#63
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(Original post by !Laxy!)
is that a no?
i have the mark scheme if u want to calculate anything...sorry i know its not what u wanted thou :cool:
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habosh
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#64
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#64
(Original post by Womble548)
I am about the answers, not about the working there as I was trying to remeber the question
yeah I ,mean the answers youve posted earlier are you sure they are right?? :confused:
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faa
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#65
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(Original post by Womble548)
I got 3.06, some people got 3.07. I think it depends when/if you rounded the speed of the particle or kept it at 24-sqrt220
hang on- how did you do it again?
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!Laxy!
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#66
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(Original post by ThugzMansion7)
i have the mark scheme if u want to calculate anything...sorry i know its not what u wanted thou :cool:
its just that i did the exam in June and got 91/100 and i know i mucked up the vectors question. I was just wondering was the boundary for an A was.
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TheWolf
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#67
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Show that after that X is removed - the particle is still in equlibriums - how did you guys do it? I showed that the force upslope is bigger than the force downslope!
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TheWolf
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#68
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And the one that bounced off the wall. What is t? I got 13.8/14.8secs or something
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faa
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#69
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(Original post by TheWolf)
Show that after that X is removed - the particle is still in equlibriums - how did you guys do it?
worked out the weight component and said that it is less than mu(R)
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Hash
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(Original post by TheWolf)
And the one that bounced off the wall. What is t? I got 13.8/14.8secs or something
i got 3.07 seconds, but the speed at C i found to be 14.8 seconds.
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TheWolf
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#71
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(Original post by faa)
worked out the weight component and said that it is less than mu(R)
wicked! got that right. how about the one that bounced off the wall. What is t? i worked out that the velocity that it bounced off the wall is minus thirty something. I assumed that the acceleration (-3ms^-2) is the same as it says that the force is unchanged, and then but p=0.
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Hash
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#72
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(Original post by TheWolf)
wicked! got that right. how about the one that bounced off the wall. What is t? i worked out that the velocity that it bounced off the wall is minus thirty something. I assumed that the acceleration (-3ms^-2) is the same as it says that the force is unchanged, and then but p=0.
velocity when it bounced off the wall was 9.2, as opposed to 38.8 (is that what you got?).
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TheWolf
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#73
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(Original post by Hash)
i got 3.07 seconds, but the speed at C i found to be 14.8 seconds.
hmm i think ive got it wrong, what was ur method?
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TheWolf
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#74
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(Original post by Hash)
velocity when it bounced off the wall was 9.2, as opposed to 38.8 (is that what you got?).
i cant remember! i just worked it out through mv-mu, and yea it seems to be -38.8 or something i got :eek:
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Hash
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#75
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(Original post by TheWolf)
i cant remember! i just worked it out through mv-mu, and yea it seems to be -38.8 or something i got :eek:
yeah i also got 38.8 initially. Then I realised some mistakes in my working. For one, the speed can't increase after it bounces off the wall.
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faa
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#76
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i got v to equal 10??!!
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habosh
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#77
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#77
alot of stuff is similar to what I've got but I still think the vector thing at the end is not convencing
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habosh
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#78
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#78
(Original post by faa)
i got v to equal 10??!!
wrong I guess,i didn't get any 10
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faa
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#79
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#79
mv-mu=2.4

divide all through by 0.1

v-14=24

v = 38 ???%£%$£$&% lol
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habosh
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#80
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#80
but it's reversed so it turn into +
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