A level biology help about electron transport chain???

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cow033
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#1
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Im so confused about the end of the electron transport chain; oxygen is the last 'electron acceptor', and it joins with H+ proton to form water.
So does it accept both an electron and a proton??
And at the start of the electron chain when NADH is oxidised to NAD+, it loses and electron to the electron transport chain, but is an H+ also removed for the whole chemiosmosis part????
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qwert7890
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(Original post by cow033)
Im so confused about the end of the electron transport chain; oxygen is the last 'electron acceptor', and it joins with H+ proton to form water.
So does it accept both an electron and a proton??
And at the start of the electron chain when NADH is oxidised to NAD+, it loses and electron to the electron transport chain, but is an H+ also removed for the whole chemiosmosis part????
Yes, the oxygen accepts both electrons and protons to form water. But technically it accepts electrons and reacts with H+ to form water, you can’t really ‘accept’ an atom.

The reaction is:

0.5 O2 + 2e- + 2H+ ==> H2O
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qwert7890
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(Original post by cow033)
Im so confused about the end of the electron transport chain; oxygen is the last 'electron acceptor', and it joins with H+ proton to form water.
So does it accept both an electron and a proton??
And at the start of the electron chain when NADH is oxidised to NAD+, it loses and electron to the electron transport chain, but is an H+ also removed for the whole chemiosmosis part????
Yes, an H+ is also removed for the entire chemiosmosis part. These H+ are first actively pumped out into the inter membrane space in a mitochondria, and then passively flow down through the H+ channel which also acts as an ATP synthase.

So in reality, the NADH loses both proton and electrons. The reaction is:

NADH ==> NAD^+ + H+ +2e-
Last edited by qwert7890; 1 year ago
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Jpw1097
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(Original post by qwert7890)
Yes, an H+ is also removed for the entire chemiosmosis part. These H+ are first actively pumped out into the inter membrane space in a mitochondria, and then passively flow down through the H+ channel which also acts as an ATP synthase.

So in reality, the NADH loses both proton and electrons. The reaction is:

NADH ==> NAD^+ + H+ +1e-
* + 2e-
Last edited by Jpw1097; 1 year ago
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qwert7890
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(Original post by Jpw1097)
* + 2e-
Sorry, I’ll edit that !
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cow033
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(Original post by qwert7890)
Yes, an H+ is also removed for the entire chemiosmosis part. These H+ are first actively pumped out into the inter membrane space in a mitochondria, and then passively flow down through the H+ channel which also acts as an ATP synthase.

So in reality, the NADH loses both proton and electrons. The reaction is:

NADH ==> NAD^+ + H+ +2e-
thank you so much that makes sense
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