# Help! AQA Chemistry - Working out the limiting reactant (Moles etc.)

#1
a mixture contains 1.00 kg of aluminium and 3.00 kg of iron oxide

the equation for the reaction is 2Al + Fe2O3 → 2Fe + Al2O3

Show that aluminium is the limiting reactant

Ar O = 16, Al = 27, Fe = 56
Last edited by y7wvtn; 1 year ago
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1 year ago
#2
(Original post by y7wvtn)
a mixture contains 1.00 kg of aluminium and 3.00 kg of iron oxide

the equation for the reaction is 2Al + Fe2O3 → 2Fe + Al2O3

Show that aluminium is the limiting reactant

Ar O = 16, Al = 27, Fe = 56
0
1 year ago
#3
(Original post by charco)
Is it that, we convert the kg to g, then we find the mole of aluminium and do the ratio?
0
1 year ago
#4
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#5
(Original post by charco)
I'm asking for help, sorry didn't make that clear
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1 year ago
#6
(Original post by y7wvtn)
I'm asking for help, sorry didn't make that clear
sweetescobar

Respected Member

gave you the routemap
0
1 year ago
#7
First, calculate both Al and Fe2O3 number of moles; then 1/2 x number of mole (Al) = number of moles (Fe2O3); then put the number of moles of both reactants into the ratio, and finally you get the answer.
For the mass unit, it is needed to use gram because molar mass in unit of g/mol
Last edited by deskochan; 1 year ago
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1 year ago
#8
ye i know but what is the answer?
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1 year ago
#9
(Original post by TurandeMaster)
ye i know but what is the answer?
1/2 x number of mole (Al) = number of moles (Fe2O3)
1/2 x (1000/27) < 3000/(56x2+3x16)
Thus Al is the limiting reagent
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