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Help! AQA Chemistry - Working out the limiting reactant (Moles etc.)
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y7wvtn
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#1
a mixture contains 1.00 kg of aluminium and 3.00 kg of iron oxide
the equation for the reaction is 2Al + Fe2O3 → 2Fe + Al2O3
Show that aluminium is the limiting reactant
Ar O = 16, Al = 27, Fe = 56
the equation for the reaction is 2Al + Fe2O3 → 2Fe + Al2O3
Show that aluminium is the limiting reactant
Ar O = 16, Al = 27, Fe = 56
Last edited by y7wvtn; 1 year ago
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charco
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#2
(Original post by y7wvtn)
a mixture contains 1.00 kg of aluminium and 3.00 kg of iron oxide
the equation for the reaction is 2Al + Fe2O3 → 2Fe + Al2O3
Show that aluminium is the limiting reactant
Ar O = 16, Al = 27, Fe = 56
a mixture contains 1.00 kg of aluminium and 3.00 kg of iron oxide
the equation for the reaction is 2Al + Fe2O3 → 2Fe + Al2O3
Show that aluminium is the limiting reactant
Ar O = 16, Al = 27, Fe = 56
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sweetescobar
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(Original post by charco)
... and your ideas are?
... and your ideas are?
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charco
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y7wvtn
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(Original post by charco)
... and your ideas are?
... and your ideas are?
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charco
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#6
(Original post by y7wvtn)
I'm asking for help, sorry didn't make that clear
I'm asking for help, sorry didn't make that clear
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gave you the routemap
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deskochan
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#7
First, calculate both Al and Fe2O3 number of moles; then 1/2 x number of mole (Al) = number of moles (Fe2O3); then put the number of moles of both reactants into the ratio, and finally you get the answer.
For the mass unit, it is needed to use gram because molar mass in unit of g/mol
For the mass unit, it is needed to use gram because molar mass in unit of g/mol
Last edited by deskochan; 1 year ago
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TurandeMaster
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#9
(Original post by TurandeMaster)
ye i know but what is the answer?
ye i know but what is the answer?
1/2 x (1000/27) < 3000/(56x2+3x16)
Thus Al is the limiting reagent
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