Back
to top
Biology 2021 AQA Assessment materials UNOFFICIAL MARKSCHEME
Watch this threadPage 1 of 1
Go to first unread
Skip to page:
kate_howard_1
Badges:
11
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#1
Hi! These questions that are released are most likely going to be used on upcoming a level 2021 mini exams however, a mark scheme hasn't been released? Does anyone want to help make an unofficial markscheme?
1
reply
svalen123
Badges:
1
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#2
ruqayyaha
Badges:
4
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#3
Report
#3
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
5
reply
Bingsuze
Badges:
9
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#4
Report
#4
(Original post by ruqayyaha)
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
0
reply
m4inotn4
Badges:
8
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#5
Report
#5
(Original post by ruqayyaha)
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
0
reply
obj2345
Badges:
7
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#6
Report
#6
(Original post by ruqayyaha)
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
0
reply
Mishal__01
Badges:
4
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#7
Report
#7
(Original post by kate_howard_1)
Hi! These questions that are released are most likely going to be used on upcoming a level 2021 mini exams however, a mark scheme hasn't been released? Does anyone want to help make an unofficial markscheme?
Hi! These questions that are released are most likely going to be used on upcoming a level 2021 mini exams however, a mark scheme hasn't been released? Does anyone want to help make an unofficial markscheme?
Last edited by Mishal__01; 1 year ago
0
reply
Maya.kg16
Badges:
11
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#8
Report
#8
(Original post by ruqayyaha)
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
0
reply
Maya.kg16
Badges:
11
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#9
Report
#9
I'm not sure where your answer came from for 5.2, can someone explain? Also some more answers based on what I got:
4.4 a transmission electron microscope allows you to see inside the cell, whereas a scanning electron microscope only allows you to see the surface
4.5 I got 4.71 x 10^5 (that may need checking)
3.1 James Watson and Francis Crick
3.2 DNA Polymerase
3.3 1. Acts as template strand for dna nucleotides to attach to
2. To attach to the template strand to form the second strand of DNA
4.1 both are passive some don’t require ATP
Both involve substance moving down concentration gradient
4.2The concentration of monosaccharides is greater outside the epithelial cells than inside, so the monosaccharides move from the higher concentration (outside) of monosaccharides to a lower concentration (inside), hence the uptake is increasing.
The graph plateaus as the concentration inside compared to outside the epithelial cells has reached equilibrium to there is no net movement of monosaccharides.
4.4 a transmission electron microscope allows you to see inside the cell, whereas a scanning electron microscope only allows you to see the surface
4.5 I got 4.71 x 10^5 (that may need checking)
3.1 James Watson and Francis Crick
3.2 DNA Polymerase
3.3 1. Acts as template strand for dna nucleotides to attach to
2. To attach to the template strand to form the second strand of DNA
4.1 both are passive some don’t require ATP
Both involve substance moving down concentration gradient
4.2The concentration of monosaccharides is greater outside the epithelial cells than inside, so the monosaccharides move from the higher concentration (outside) of monosaccharides to a lower concentration (inside), hence the uptake is increasing.
The graph plateaus as the concentration inside compared to outside the epithelial cells has reached equilibrium to there is no net movement of monosaccharides.
0
reply
X
Page 1 of 1
Go to first unread
Skip to page:
Quick Reply
