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Biology 2021 AQA Assessment materials UNOFFICIAL MARKSCHEME
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Hi! These questions that are released are most likely going to be used on upcoming a level 2021 mini exams however, a mark scheme hasn't been released? Does anyone want to help make an unofficial markscheme?
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#3
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
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#4
(Original post by ruqayyaha)
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
0
reply
Report
#5
(Original post by ruqayyaha)
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
0
reply
Report
#6
(Original post by ruqayyaha)
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
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reply
Report
#7
(Original post by kate_howard_1)
Hi! These questions that are released are most likely going to be used on upcoming a level 2021 mini exams however, a mark scheme hasn't been released? Does anyone want to help make an unofficial markscheme?
Hi! These questions that are released are most likely going to be used on upcoming a level 2021 mini exams however, a mark scheme hasn't been released? Does anyone want to help make an unofficial markscheme?
Last edited by Mishal__01; 3 weeks ago
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#8
(Original post by ruqayyaha)
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
AS - BIOLOGICAL MOLECULES
1.1)BDAB
1.2) 18, 36 ,18
1.3) hydrolyse raffinose solution by heating with dilute hydrochloric acid. Neutralise solution by adding sodium hydrogencarbonate and then carry out benedict's test by adding benedict's reagent to the solution and heat in a water bath. Positive reult = orange - red precipitate.
5.1) 1. Cells at the tip of onion root are dividing
2. to form a thin layer so light can pass through and make cells visible.
5.2) 3/32 * 1082 = 101.25 mins
105-101.25/105 * 100 = 3.57%
5.3) cytokinesis
5.4) dont really know
8.1) use biuret test. Add sodium hydroxide into test tube containing sample and add few drops of dilute copper (II) sulfate and mix. should go from blue to purple
8.2) 1. have carbon, oxygen, hydrogen and nitrogen
2. formed through condensation reactions
difference: have different chemical and physical properties
8.3) theyre moving towards negative electrode si both amino acids are positivley charged.
5.3) a competitive inhibitor has a shape similar to the substrate which is complementary to shape of the active site. They bind to the active site so substrate cant bind.
1.1) BAE
1.2) More mitochondria makes more ATP which needed for protein synthesis and trasnport of proteins. Many golgi vesicles needed for vesicular transport of proteins out of cell.
4.2) cell not stained to show nucleas
4.3) S=large vacuole
T= chloroplasts
4.4) transmission electron microscopes can be used
ill do some later, hope this helps
Last edited by lil_lily__; 13 minutes ago
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