linear programming question

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#1
for part a, I got 6-x-y

I am confused on part b)i), I simplified 5x+3y+2(6-x-y) but that gives me 3x+y+12. If I substitute -x-y I get 3x+y but I am not sure why I should substitute -x-y and not 6-x-y.

Any help will be much appreciated
Last edited by machau; 1 month ago
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1 month ago
#2
(Original post by machau)
for part a, I got 6-x-y

I am confused on part b)i), I simplified 5x+3y+2(6-x-y) but that gives me 3x+y+12. If I substitute -x-y I get 3x+y but I am not sure why I should substitute -x-y and not 6-x-y.

Any help will be much appreciated
You want to maximize it. What difference does the +12 make?
Last edited by mqb2766; 1 month ago
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#3
(Original post by mqb2766)
You want to maximize it. What difference does the +12 make?
Sorry I'm not sure I understand, the +12 will increase P by 12?
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1 month ago
#4
(Original post by machau)
Sorry I'm not sure I understand, the +12 will increase P by 12?
Suppose f is a function of x and y. If you find x and y that maximize f, they're also going to maximize f+12...
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#5
(Original post by DFranklin)
Suppose f is a function of x and y. If you find x and y that maximize f, they're also going to maximize f+12...
oh right, yes I understand now. thank you
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1 month ago
#6
(Original post by machau)
oh right, yes I understand now. thank you
The important thing to realize is that you're searching for the values of x and y that maximize the function. You're not directly interested in finding the value of the function itself. You could multiply the function by a positive constant, and the location of the maximum would be unchanged. Multiplying the function by a negative constant turns a maximization problem into a minimization problem etc.
Last edited by mqb2766; 1 month ago
0
#7
(Original post by mqb2766)
The important thing to realize is that you're searching for the values of x and y that maximize the function. You're not directly interested in finding the value of the function itself. You could multiply the function by a positive constant, and the location of the maximum would be unchanged. Multiplying the function by a negative constant turns a maximization problem into a minimization problem etc.
thank you!
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