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Chemistry question help

Hi, im stuck with this question. I worked out the moles of the bromine solution. Then stoichiometry, then rearranged but got lost and im not sure. I would appreciate a step by step process of the calculation please. Any help appreciated. Thanks in advance
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(edited 2 years ago)
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Original post by kristenVigil
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how do you know there is 2 moles of bromine
thanks btw :smile:
(edited 2 years ago)
Original post by chemhelpthanks
how do you know there is 2 moles of bromine
thanks btw :smile:

Bromine reacts with limonene via electrophilic addition(add across double bonds), 2 double bonds present in limonene hence 2:1 ratio
Original post by kristenVigil
Bromine reacts with limonene via electrophilic addition(add across double bonds), 2 double bonds present in limonene hence 2:1 ratio

ahh right, thanks a lot
Did you get 83.3%?


I did this:

3.06x10^-3 x 136 (rfm of limonene) = 0.41616

0.41616/0.500 x100 = 83.3%

But on this website someone said its 83.4% ....https://chemistry.stackexchange.com/questions/150988/mass-percentage-of-limonene-in-a-sample
(edited 2 years ago)
Original post by bubblebubble1234
Did you get 83.3%?


I did this:

3.06x10^-3 x 136 (rfm of limonene) = 0.41616

0.41616/0.500 x100 = 83.3%

But on this website someone said its 83.4% ....https://chemistry.stackexchange.com/questions/150988/mass-percentage-of-limonene-in-a-sa

I got 83.3

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