user342
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Am I wrong to try to use v^2=u^2+2as for this, with u and a being perp to the slope instead of parallel, and therefore v is 0? Name:  B24C9D28-9D22-456A-B73C-A08E58C429A9.png
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mqb2766
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If you use v^2 = u^2 +2as perpendicular to the slope, you can find the maximum height, but you really need to relate this to the parallel to the slope distance. Time to peak would be a more natural/direct way of doing this rather than peak height? This is what the model solution seems to do.

So its not incorrect to use it, but its a less direct way and generally you choose your suvat equation to directly relate the variables of interest, rather than for solving for ones you dont really need.
Last edited by mqb2766; 1 month ago
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user342
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(Original post by mqb2766)
If you use v^2 = u^2 +2as perpendicular to the slope, you can find the maximum height, but you really need to relate this to the parallel to the slope distance. Time to peak would be a more natural/direct way of doing this rather than peak height? This is what the model solution seems to do.

So its not incorrect to use it, but its a less direct way and generally you choose your suvat equation to directly relate the variables of interest, rather than for solving for ones you dont really need.
Ok, thank you 😊
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