H_harre
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Hi there, I’m stuck on a question that gose:
The student records the following data:

Separation of the two loudspeakers =0.30 m
Distance OA =2.25m
Distance from A to B =0.95 m

Show the path difference for the sound waves from the two loudspeakers to point B is about 0.1m

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Last edited by H_harre; 4 weeks ago
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vicgb03
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path diff.=nλ (where λ=wavelength) and apparently n=1, so the path difference=λ
You also know that λ=ax/D
where a=0.3m, x=0.95m and D=2.25m
therefore λ= (0.3*0.95)/2.25 =0.13 (0.1m)
(so path difference= about 0.1m)

Hope this helps!
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H_harre
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(Original post by vicgb03)
path diff.=nλ (where λ=wavelength) and apparently n=1, so the path difference=λ
You also know that λ=ax/D
where a=0.3m, x=0.95m and D=2.25m
therefore λ= (0.3*0.95)/2.25 =0.13 (0.1m)
(so path difference= about 0.1m)

Hope this helps!
I get it now, Thankyou very much
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