# removed

Watch
Announcements
#1
..
Last edited by Arb.dha; 1 month ago
0
1 month ago
#2
Use factor theorem. If you sub in the value of x into p(x) and you get 0, it’s a factor
0
#3
(Original post by Anon???)
Use factor theorem. If you sub in the value of x into p(x) and you get 0, factor
I tried that. The following questions ask for that and it said they're right. it said this isn't I'm not sure why.
0
1 month ago
#4
Post the actual question.
0
#5
(Original post by DFranklin)
Post the actual question.
I've edited now
0
1 month ago
#6
(Original post by Arb.dha)
I've edited now

Secondly, look at your original post:

(Original post by Arb.dha)
the cubic function p(x)=2x^3 x^2 -13x 6
You have not stated the signs on some of the terms. This therefore has several possibilities:

There are some tricks to factoring polynomials but a lot of the time it is simply just a case of trial and error. So just plug in some numbers and try.

The process of what you are really doing is as follows. You want to get something of the form:

Note that we can write it like this because I presume the question implies that it can be reduced to a simpler form. This is not always the case - sometimes you cannot find any factors!

Here, can be any rational number from the list you've given and this is where trial and error is needed. You need to figure out if or if etc.

Note that and are the coefficients and is a real number. You can use polynomial division to find the second polynomial, i.e.:

:

If you need to determine , then you need to use something called the "zero product property of real numbers". This is a fancy way of saying the following. If you have two real numbers and , if their product is , then either or or both must be zero.

In your original polynomial, you have:

Here is one number and the other number is . Therefore you can write and and solve accordingly after you have figured out all the factors.
Last edited by 0le; 1 month ago
2
1 month ago
#7
(Original post by Arb.dha)
Can anyone help?
I have the following question:
the cubic function p(x)=2x^3 x^2 -13x 6
which of the following are possible factors of p(x)?
x /- 1
x /-2
x /-3
x /-4
x /-6
x /-0.5
x /-1.5
I have tried to factorise it. that doesn't get the right answer. You can pick multiple ones but I just don't understand how to get to the answer. Can anyone help?
Edit: attached image
Attachment 1020387
It's a stupid question. Especially when you're then asked to find the factors and you get it right.

What's their definition of a "possible factor"? It's either a factor or it isn't.

I know what the intention is but having seen a student using this online course I know that there's a problem with this question.
1
X

new posts
Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### Poll

Join the discussion

#### Do you think receiving Teacher Assessed Grades will impact your future?

I'm worried it will negatively impact me getting into university/college (183)
43.68%
I'm worried that I’m not academically prepared for the next stage in my educational journey (48)
11.46%
I'm worried it will impact my future career (33)
7.88%
I'm worried that my grades will be seen as ‘lesser’ because I didn’t take exams (89)
21.24%
I don’t think that receiving these grades will impact my future (42)
10.02%
I think that receiving these grades will affect me in another way (let us know in the discussion!) (24)
5.73%