Secondly, look at your original post:
There are some tricks to factoring polynomials but a lot of the time it is simply just a case of trial and error. So just plug in some numbers and try.
The process of what you are really doing is as follows. You want to get something of the form:
Note that we can write it like this because I presume the question implies that it can be reduced to a simpler form. This is not always the case - sometimes you cannot find any factors!
Here, can be any rational number from the list you've given and this is where trial and error is needed. You need to figure out if or if etc.
Note that and are the coefficients and is a real number. You can use polynomial division to find the second polynomial, i.e.:
If you need to determine , then you need to use something called the "zero product property of real numbers". This is a fancy way of saying the following. If you have two real numbers and , if their product is , then either or or both must be zero.
In your original polynomial, you have:
Here is one number and the other number is . Therefore you can write and and solve accordingly after you have figured out all the factors.
Can anyone help?
I have the following question:
the cubic function p(x)=2x^3 x^2 -13x 6
which of the following are possible factors of p(x)?
x /- 1
I have tried to factorise it. that doesn't get the right answer. You can pick multiple ones but I just don't understand how to get to the answer. Can anyone help?
Edit: attached image
What's their definition of a "possible factor"? It's either a factor or it isn't.
I know what the intention is but having seen a student using this online course I know that there's a problem with this question.