# Inequalities question

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#1
Hi can somebody solve this AS 6 marker for me please:
Given x≠1, find 3/(x-1) < 2

I get x>5/2 but don't understand why x<1
Thank you
Last edited by Rhys_M; 1 month ago
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1 month ago
#2
(Original post by Rhys_M)
Hi can somebody solve this AS 6 marker for me please:
Given x≠1, find 3/(x-2) < 2

I get x>5/2 but don't understand why x<1
Thank you
Can you post the original question and your solution pls, as per normal.
Last edited by mqb2766; 1 month ago
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#3
(Original post by mqb2766)
Can you post the original question and your solution pls, as per normal.
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1 month ago
#4
(Original post by Rhys_M)
Note the question is different from what you posted.
From line 1 to line 2 in your solution, what do you assume?

Alternatively, stick a few values in / sketch the original function (desmos?) to check.
Last edited by mqb2766; 1 month ago
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1 month ago
#5
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1 month ago
#6
(Original post by mqb2766)
Was only trying to help
1
#7
(Original post by Georgiaspriggs)
Was only trying to help
Yea i appreciate it - he's really rude
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1 month ago
#8
(Original post by Rhys_M)
Yea i appreciate it - he's really rude
Also another good app for maths I think is photo math.
I think people assume it’s just good for finding the answer but when you are really stuck it talks you through how to solve good luck
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1 month ago
#9
(Original post by Rhys_M)
Yea i appreciate it - he's really rude
There was nothing rude in my replies.
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#10
(Original post by Georgiaspriggs)
Also another good app for maths I think is photo math.
I think people assume it’s just good for finding the answer but when you are really stuck it talks you through how to solve good luck
Yea I'll try it - thanks mate
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1 month ago
#11
(Original post by Georgiaspriggs)
Was only trying to help
(Original post by Rhys_M)
Yea i appreciate it - he's really rude
If you're planning to post in the Maths forum regularly, please take a moment to read through the posting guidelines in the Sticky thread in this forum:

https://www.thestudentroom.co.uk/sho....php?t=4919248

In particular please note that we give hints and guidance, not full solutions, and it always helps to see a picture of the original question as posters often mistype things (as happened here ). Thanks.
1
#12
(Original post by davros)
If you're planning to post in the Maths forum regularly, please take a moment to read through the posting guidelines in the Sticky thread in this forum:

https://www.thestudentroom.co.uk/sho....php?t=4919248

In particular please note that we give hints and guidance, not full solutions, and it always helps to see a picture of the original question as posters often mistype things (as happened here ). Thanks.
Ok i will - thanks
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1 month ago
#13
(Original post by Rhys_M)
Yea i appreciate it - he's really rude
Regular posters here (the people who can and might help you) know that mqb2766 spends a lot of time helping students here often without thanks and for no personal gain.

Who's rude?
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1 month ago
#14
(Original post by Rhys_M)
Ok i will - thanks
An apology and editing your rude comment would be goid
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#15
(Original post by Muttley79)
An apology and editing your rude comment would be goid
Another guy tried to help me and mqb told him not to and let the OPs do it - which i think is kinda rude considering the guy was trying to help me
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1 month ago
#16
(Original post by Rhys_M)
Another guy tried to help me and mqb told him not to and let the OPs do it - which i think is kinda rude considering the guy was trying to help me
Yes because 'the other guy' was breaking forum rules ... mqb spends a lot of time helping people.
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1 month ago
#17
Im just gong to make one post on this and then leaving it. The sticky says
* not to offer extra hints/help if help is already being offered
... As the other poster clearly stated the error that had been made, I asked them to delete it for those reasons.

As a reflection why, assuming the multiplier/divisor is +ive in an inequality is a reasonably common mistake to make. Usually its good to be able to figure out ways yourself to identify such problems. As well as sketching and/or subbing values into the function as one way to verify an answer (which was suggested originally to help and could have been used to work out whether the OP or the MS was correct), I was going to suggest trying
1/x < 1
whch is a gcse reciprocal function which has all the properties of the question. That graph/answre should be well known and the question is just a simple transformation of it.

So I was trying to encourage the OP to debug/validate their solution (subbing values, sketching, simplifying). I had a quick look through previous posting history and I've helped them a few times previously.
Last edited by mqb2766; 1 month ago
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