hypan6
Badges: 3
Rep:
?
#1
Report Thread starter 4 weeks ago
#1
A car is travelling on a straight horizontal road, the velocity of the car v ms^-1 at time t seconds as it passes three point, P Q and R. It is modelled by the equation v=at^2+bt+c
The car passes P at time t=0 with velocity 8ms-1
c=8
The car passes Q at t=5 and at that instant its deceleration is 0.12 ms-2
The car passes R at t=18 with velocity 2.96 ms-1
b) determine the value of a and b
c) find to the nearest metre the distance between points P and R
0
reply
hypan6
Badges: 3
Rep:
?
#2
Report Thread starter 4 weeks ago
#2
Please help
0
reply
hypan6
Badges: 3
Rep:
?
#3
Report Thread starter 4 weeks ago
#3
Why do you all hate me ;-;
0
reply
hypan6
Badges: 3
Rep:
?
#4
Report Thread starter 4 weeks ago
#4
*cries*
1
reply
hypan6
Badges: 3
Rep:
?
#5
Report Thread starter 4 weeks ago
#5
Please hjelp me
0
reply
Bruh Moment #293
Badges: 5
Rep:
?
#6
Report 4 weeks ago
#6
(Original post by hypan6)
Please hjelp me
Dont worry brother i got you
between q and r it has been 13seconds, 2.96/0.12 = 230
as your initial velocity is 8, a must be 8 and b must be 238
The distance between p and r is 230/13 = 17.7
1
reply
M_Thomson
Badges: 3
Rep:
?
#7
Report 4 weeks ago
#7
(Original post by Bruh Moment #293)
Dont worry brother i got you
between q and r it has been 13seconds, 2.96/0.12 = 230
as your initial velocity is 8, a must be 8 and b must be 238
The distance between p and r is 230/13 = 17.7
Yeah, that's what I got
1
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

Should the school day be extended to help students catch up?

Yes (78)
29%
No (191)
71%

Watched Threads

View All
Latest
My Feed