# maths

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Thread starter 4 weeks ago
#1
hi, i’m really stuck with this questions, it is -

find the equation of the straight line passing through the point (0,-1) which is perpendicular to the line

y=-3/4x-3

any help would be appreciated
thank you
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4 weeks ago
#2
when a line is perpendicular, the gradient is the negative reciprocal to the gradient, so as the gradient is -3/4x the negative reciprocal to the would be 4/3x (if it was 3x for example it would become -1/3x)
The question tells you that the it passes through (0, -1) with 0 being the x cordinate and -1 being the y coordinate, and you can now substitute this into the formula y = 4/3x + c -1 = 4/3 x 0 +c
Solve the equation: -1 = 0 + c -1 = c you now know that -1 is the y intercept and this can be put into the equation
y = 4/3 x - 1
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