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Hardy-Weinberg

Can someone explain how the answer is 32% for question 7.5 (page 23 of: https://filestore.aqa.org.uk/sample-papers-and-mark-schemes/2017/june/AQA-74022-QP-JUN17.PDF).

I initially tried using p=0.6 and q=0.4 to find 2pq, but got 0.48 which is incorrect.

Just noticed I accidentally posted this in the maths forum :/
(edited 2 years ago)
Original post by Pyruvic Acid
Can someone explain how the answer is 32% for question 7.5 (page 23 of: https://filestore.aqa.org.uk/sample-papers-and-mark-schemes/2017/june/AQA-74022-QP-JUN17.PDF).

I initially tried using p=0.6 and q=0.4 to find 2pq, but got 0.48 which is incorrect.

Just noticed I accidentally posted this in the maths forum :/

Not sure how you managed to get p=0.6 , but what I did was figure that the percentage of green fruit is 64% (given there's only green and yellow fruit) so q^2 = 0.64, therefore q = 0.8 and p = 1-q = 0.2 so 2pq = 2*0.8*0.2 = 0.32 or 32%
Original post by maria_2020
Not sure how you managed to get p=0.6 , but what I did was figure that the percentage of green fruit is 64% (given there's only green and yellow fruit) so q^2 = 0.64, therefore q = 0.8 and p = 1-q = 0.2 so 2pq = 2*0.8*0.2 = 0.32 or 32%

Thanks! :smile:

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