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what's the question

**Isabel Steele**)what's the question

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#4

the first answer i thin is acceleration and the second = 3/20 = 0.15m/s

the reason that it is 4 irks is because you put down formula, working out, final answer and units.

the reason that it is 4 irks is because you put down formula, working out, final answer and units.

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(Original post by

the first answer i thin is acceleration and the second = 3/20 = 0.15m/s

the reason that it is 4 irks is because you put down formula, working out, final answer and units.

**Isabel Steele**)the first answer i thin is acceleration and the second = 3/20 = 0.15m/s

the reason that it is 4 irks is because you put down formula, working out, final answer and units.

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#6

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hi is that for the second part becuase i completelty forgot to say that it was the second question the 4 marker that i needed help on

**Madz178**)hi is that for the second part becuase i completelty forgot to say that it was the second question the 4 marker that i needed help on

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#7

I don't think you can do 2.8/20, as the car is accelerating. s = d/t only works for constant speed. If they give you the acceleration, you could use the acceleration equation. If they tell you that the acceleration is constant, you could use a SUVAT formula. If they give you the equation of the curve, you could differentiate. If not, you could draw on a tangent to the curve when x = 20, and find the gradient of the curve, although this is less accurate.

Please correct me if you think that's wrong! But I'm pretty sure you can't just do s = d/t

Please correct me if you think that's wrong! But I'm pretty sure you can't just do s = d/t

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#8

(Original post by

I don't think you can do 2.8/20, as the car is accelerating. s = d/t only works for constant speed. If they give you the acceleration, you could use the acceleration equation. If they tell you that the acceleration is constant, you could use a SUVAT formula. If they give you the equation of the curve, you could differentiate. If not, you could draw on a tangent to the curve when x = 20, and find the gradient of the curve, although this is less accurate.

Please correct me if you think that's wrong! But I'm pretty sure you can't just do s = d/t

**chipperpotato**)I don't think you can do 2.8/20, as the car is accelerating. s = d/t only works for constant speed. If they give you the acceleration, you could use the acceleration equation. If they tell you that the acceleration is constant, you could use a SUVAT formula. If they give you the equation of the curve, you could differentiate. If not, you could draw on a tangent to the curve when x = 20, and find the gradient of the curve, although this is less accurate.

Please correct me if you think that's wrong! But I'm pretty sure you can't just do s = d/t

However, you have actually made an excellent point in that the question may have given some additional information earlier on which the user has not provided us. I have only just spotted that this is parts four and five of Question 6!

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#9

(Original post by

You may be right, but I believe that would give you the instantaneous velocity. The average velocity could still be calculated using s = d/t. Unfortunately the question is not particularly clear either way.

However, you have actually made an excellent point in that the question may have given some additional information earlier on which the user has not provided us. I have only just spotted that this is parts four and five of Question 6!

**0le**)You may be right, but I believe that would give you the instantaneous velocity. The average velocity could still be calculated using s = d/t. Unfortunately the question is not particularly clear either way.

However, you have actually made an excellent point in that the question may have given some additional information earlier on which the user has not provided us. I have only just spotted that this is parts four and five of Question 6!

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Yes, I think there must be more information as this looks as if it is from an official exam paper and I think it's really unlikely that they wouldn't specify that they wanted average speed, if this is what they were looking for!

**chipperpotato**)Yes, I think there must be more information as this looks as if it is from an official exam paper and I think it's really unlikely that they wouldn't specify that they wanted average speed, if this is what they were looking for!

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#11

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hi thanks for all your comments and help but this was on the 2021 additional assessment materials that aqa had released- the materials released are from past paper questions some from released papers and some unreleased and these are just bits - this is the whole question that i have given you if you would like to see for yourself here is the link for the materials - https://www.aqa.org.uk/2021-exam-cha...als#assessment go on to the bottom where it says get the support materials click gcse and physics and the paper is test 4 forces- higher

**Madz178**)hi thanks for all your comments and help but this was on the 2021 additional assessment materials that aqa had released- the materials released are from past paper questions some from released papers and some unreleased and these are just bits - this is the whole question that i have given you if you would like to see for yourself here is the link for the materials - https://www.aqa.org.uk/2021-exam-cha...als#assessment go on to the bottom where it says get the support materials click gcse and physics and the paper is test 4 forces- higher

The only way to find the speed, or an estimate for the speed, would be to draw on a tangent. I don't know whether that's part of the AQA spec though!

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