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Calculation of water of crystallization

If 0.465g Of hydrated sodium carbonate reacted completely with 75cm³ of a 0.1M hydrochloric acid. Calculate the number of moles of water of crystallization present in one mole of the hydrated salt.
0.465g Of hydrated sodium carbonate reacted completely with 75cm³ of a 0.1M hydrochloric acid. Calculate the number of moles of water of crystallization present in one mole of the hydrated salt.
(edited 2 years ago)
Any ideas?
Reply 3
what have you tried?
What have you done so far - have you formed the equation?

Na2CO3.xH2O + 2 HCl -> 2 NaCl + CO2 + (x+1) H2O
first step, find number of moles of HCl by relating 0.1moles equals to 1000cm3 what about 75cm3? then after write the chemical equation,the reaction between Sodium carbonate and HCl, make relation between the moles of HCl and moles of Sodium carbonate to get the moles of sodium carbonate. finally use the formula molar mass of hydrated divide by molar mass of unhydrous equals to mass of hydrated divide by mass of unhydrous

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