# Absolute Value Inequalities - Math Question

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#1
Does anyone know how to solve this?
|x+2k| > |x-k|
I need to find what k is
and k is a positive constant
0
4 weeks ago
#2
Yes, but I don't believe we can just provide solutions.
What have you attempted?
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#3
(Original post by Maths Fan)
Yes, but I don't believe we can just provide solutions.
What have you attempted?
hold on, I'll upload my working out
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4 weeks ago
#4
It may help you to also have a read through Chapter 0, Section 0.5 of Stitz and Zeager, which goes through inequalities of absolute terms:

https://www.stitz-zeager.com/

Page 55 has some worked examples.
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#5
(Original post by Maths Fan)
Yes, but I don't believe we can just provide solutions.
What have you attempted?
0
#6
(Original post by 0le)
It may help you to also have a read through Chapter 0, Section 0.5 of Stitz and Zeager, which goes through inequalities of absolute terms:

https://www.stitz-zeager.com/

Page 55 has some worked examples.
Thank you! I'll check them out
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#7
(Original post by 0le)
It may help you to also have a read through Chapter 0, Section 0.5 of Stitz and Zeager, which goes through inequalities of absolute terms:

https://www.stitz-zeager.com/

Page 55 has some worked examples.
There's unfortunately nothing for absolute value inequalities WITH constants...
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4 weeks ago
#8
In red: The first line is correct, the second isn't. You have to multiply BOTH sides by -1 when flipping the inequality.

Note: you could divide through by k at this point as it's a positive quantity.

Last edited by ghostwalker; 4 weeks ago
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#9
(Original post by ghostwalker)
In red: The first line is correct, the second isn't. You have to multiply BOTH sides by -1 when flipping the inequality.

Note: you could divide through by k at this point as it's non-zero.

Thank you so much for pointing that out!!
I was finally left with k>-2x
What do I do next?
0
4 weeks ago
#10
(Original post by Kundana Amudala)
Thank you so much for pointing that out!!
I was finally left with k>-2x
What do I do next?
What does the original question actually say? Can you upload an image?
0
4 weeks ago
#11
(Original post by Kundana Amudala)
Thank you so much for pointing that out!!
I was finally left with k>-2x
What do I do next?
Note: I should have said you can cancel the k as it's a positive quantity. Just being non-zero isn't good enough with inequalities.

Well you can't go any further, other than rearrange to x> -k/2 perhaps.
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#12
(Original post by mqb2766)
What does the original question actually say? Can you upload an image?
sure
0
4 weeks ago
#13
So they want you to find a range of x (in terms of k) which you have done?

Without squaring, you could have noted one inequality is
x+2k > x-k
which is trivially satisfied, as well as the other combiations.
x+2k > -(x-k)
etc ...

If you thought about it on the number line, they want the xs which are closer to the point "k" than to the point "-2k". The midpoint -k/2 represents the boundary (equal distance from these two points). Just do a quick sketch.
Last edited by mqb2766; 4 weeks ago
0
4 weeks ago
#14
(Original post by Kundana Amudala)
There's unfortunately nothing for absolute value inequalities WITH constants...
It does not matter. The constant is not really the issue here but rather the logic. The solution using the methods described in that book is as follows:

If , then the solution is either:
or

By doing it this way, you avoid the need to work with squared terms. Sometimes, as in the case here, when you work through one of those inequalities it becomes apparent that it leads to a "dead-end" so to speak. So in your question, doing it this way leads to the two inequalities:
and

Obviously the first one does not provide any useful information since we know that k was positive anyway.

EDIT: Beaten to it above!
Last edited by 0le; 4 weeks ago
0
4 weeks ago
#15
(Original post by 0le)
It does not matter. The constant is not really the issue here but rather the logic. The solution using the methods described in that book is as follows:

If , then the solution is either:
or

By doing it this way, you avoid the need to work with squared terms. Sometimes, as in the case here, when you work through one of those inequalities it becomes apparent that it leads to a "dead-end" so to speak. So in your question, doing it this way leads to the two inequalities:
and

Obviously the first one does not provide any useful information since we know that k was positive anyway.

EDIT: Beaten to it above!
Yup and they got a free sketch as well :-)
0
#16
Thanks a lot!!
0
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