# exponential growth curve

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#1

Determine the area under the following exponential growth curve between 2 seconds and 4
seconds;
Last edited by gtdub1234; 8 months ago
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8 months ago
#2
(Original post by gtdub1234)

Determine the area under the following exponential growth curve between 2 seconds and 4
seconds;
𝑦 = 􀶱integral (1 −𝑒^-t) dt
It looks like you need to do a little reading. Do you have a textbook?
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#3
i do, where to start!

its the 1-e^-t thats getting me flustered..
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8 months ago
#4
(Original post by gtdub1234)
i do, where to start!

its the 1-e^-t thats getting me flustered..
Can you do ?

What book are you using?

Have you read the relevant chapter and worked through some examples?
Last edited by username1732133; 8 months ago
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#5
i just panic with math's, its an online HNC edexel , i think maybe i should contact the tutor.

there aren't any examples in the book of this type.

i have probably done questions that use the same method but im unsure on what method to use on this
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#6
[ 1e^1 / 1] =[e] ( with 4 & 2 @ top/bottom of brackets)

e^4 - e^2 =

54.6 - 7.39 = 47.21 sq units
Last edited by gtdub1234; 8 months ago
0
8 months ago
#7
(Original post by gtdub1234)
[ 1e^1 / 1] =[e]

e^4 - e^2 =

54.6 - 7.39 = 47.21 sq units
That's correct. I'll send a link for a textbook in a minute.
1
#8
(Original post by Plücker)
That's correct. I'll send a link for a textbook in a minute.
cheers for that!
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#9
the second part of the question is the same but without the -1 before the e...

do i work it out the same way?
Last edited by gtdub1234; 8 months ago
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8 months ago
#10
(Original post by gtdub1234)
cheers for that!

Scroll down to the bottom. Look in the year 2 pure book.

Question 5 here is similar. https://activeteach-prod.resource.pe...b_p2_ex11a.pdf
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#11
1
#12
(Original post by Plücker)
That's correct. I'll send a link for a textbook in a minute.
i have checked on an integral calculator and on a graphing simulator.
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8 months ago
#13
(Original post by gtdub1234)
i have checked on an integral calculator and on a graphing simulator.

I haven't seen an answer to the original question yet. The questions I gave you were intended to find out what you know.

is correct but your original question was .

You might find it helpful to know that but you will also eventually (very soon?) need to know some more general principles.
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#14
(Original post by gtdub1234)

Determine the area under the following exponential growth curve between 2 seconds and 4
seconds;
[ 1e^1 / 1] =[e] ( with 4 & 2 @ top/bottom of brackets)

e^4 - e^2 =

54.6 - 7.39 = 47.21 sq units
0
8 months ago
#15
(Original post by gtdub1234)
[ 1e^1 / 1] =[e] ( with 4 & 2 @ top/bottom of brackets)

e^4 - e^2 =

54.6 - 7.39 = 47.21 sq units
0
#16
(Original post by Plücker)
thats what i said...
0
8 months ago
#17
(Original post by gtdub1234)
thats what i said...
It's wrong because it's the answer to a different question.

This isn't getting you very far.

You could try having a look at the book and the example I posted earlier.
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