exponential growth curve

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gtdub1234
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#1
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#1
Please help!!

Determine the area under the following exponential growth curve between 2 seconds and 4
seconds;
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Last edited by gtdub1234; 8 months ago
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username1732133
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#2
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#2
(Original post by gtdub1234)
Please help!!

Determine the area under the following exponential growth curve between 2 seconds and 4
seconds;
𝑦 = 􀶱integral (1 −𝑒^-t) dt
It looks like you need to do a little reading. Do you have a textbook?
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gtdub1234
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i do, where to start!

its the 1-e^-t thats getting me flustered..
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username1732133
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(Original post by gtdub1234)
i do, where to start!

its the 1-e^-t thats getting me flustered..
Can you do \int_2^4 1 dt?

What about \int_2^4 e^t dt?

What book are you using?

Have you read the relevant chapter and worked through some examples?
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gtdub1234
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i just panic with math's, its an online HNC edexel , i think maybe i should contact the tutor.

there aren't any examples in the book of this type.

i have probably done questions that use the same method but im unsure on what method to use on this
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gtdub1234
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[ 1e^1 / 1] =[e] ( with 4 & 2 @ top/bottom of brackets)

e^4 - e^2 =

54.6 - 7.39 = 47.21 sq units
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username1732133
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(Original post by gtdub1234)
[ 1e^1 / 1] =[e]

e^4 - e^2 =

54.6 - 7.39 = 47.21 sq units
That's correct. I'll send a link for a textbook in a minute.
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gtdub1234
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(Original post by Plücker)
That's correct. I'll send a link for a textbook in a minute.
cheers for that!
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gtdub1234
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the second part of the question is the same but without the -1 before the e...

do i work it out the same way?
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username1732133
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#10
(Original post by gtdub1234)
cheers for that!
https://drive.google.com/drive/folde...3dkQXFRQ0NlNDA

Scroll down to the bottom. Look in the year 2 pure book.

Question 5 here is similar. https://activeteach-prod.resource.pe...b_p2_ex11a.pdf
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gtdub1234
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gtdub1234
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#12
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(Original post by Plücker)
That's correct. I'll send a link for a textbook in a minute.
this answer is completely wrong.
i have checked on an integral calculator and on a graphing simulator.
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username1732133
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(Original post by gtdub1234)
this answer is completely wrong.
i have checked on an integral calculator and on a graphing simulator.
Which answer to which question?

I haven't seen an answer to the original question yet. The questions I gave you were intended to find out what you know.

\int_2^4 e^t dt = e^4-e^2 is correct but your original question was \int_2^4 (1-e^{-t})dt .

You might find it helpful to know that \int e^{at} dt = \frac{1}{a} e^{at}+C but you will also eventually (very soon?) need to know some more general principles.
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gtdub1234
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#14
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(Original post by gtdub1234)
Please help!!

Determine the area under the following exponential growth curve between 2 seconds and 4
seconds;
Name:  integral.PNG
Views: 69
Size:  2.6 KB
[ 1e^1 / 1] =[e] ( with 4 & 2 @ top/bottom of brackets)

e^4 - e^2 =

54.6 - 7.39 = 47.21 sq units
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username1732133
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#15
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#15
(Original post by gtdub1234)
[ 1e^1 / 1] =[e] ( with 4 & 2 @ top/bottom of brackets)

e^4 - e^2 =

54.6 - 7.39 = 47.21 sq units
That is not the answer to your original question.
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gtdub1234
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#16
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#16
(Original post by Plücker)
That is not the answer to your original question.
thats what i said...
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username1732133
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#17
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#17
(Original post by gtdub1234)
thats what i said...
It's wrong because it's the answer to a different question.

This isn't getting you very far.

You could try having a look at the book and the example I posted earlier.
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