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    • Thread Starter
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    does this look right?

    4(3x - 9) + 7 = x + 4
    12x - 36 + 7 = x + 4
    12x - 29 = x + 4
    11x = 29 + 4
    x = 3
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    yup
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    Yes.
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    Most definitely.
    • Thread Starter
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    thanks, would it also be possible to check if i have done this correctly?

    1/x = 4
    1 = 4x
    x = 1/4

    <am i allowed to ask for people to check answers on tsr, or is that "breaking the rules" as such?>
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    (Original post by jermaindefoe)
    thanks, would it also be possible to check if i have done this correctly?

    1/x = 4
    1 = 4x
    x = 1/4
    It's correct.

    <am i allowed to ask for people to check answers on tsr, or is that "breaking the rules" as such?>
    I don't think so it will breaking rule.
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    Well if you wanted to check whether you have done it right just substitute the value for x back in:

    4(3x - 9) + 7 = x + 4

    4(3*3-9)+7= 3+4

    4*0+7=7

    7=7
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    (Original post by jermaindefoe)
    thanks, would it also be possible to check if i have done this correctly?

    1/x = 4
    1 = 4x
    x = 1/4

    <am i allowed to ask for people to check answers on tsr, or is that "breaking the rules" as such?>
    Breaking which rules?

    No, TSR is all about helping others! The only thing we object to is people giving us a question and saying "now wat" [sic]. :p: Provided you've shown your working, or explained your thinking and what you're stuck on, someone will always be happy to help.
    • Thread Starter
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    please could someone check my rearranging for this

    i really suck at these and i did this from just looking at a guide so i havent really learnt it :s

    y = mx + c (make x the subject)
    y + c = mx
    x = (y + c) / m
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    When you do something you have to do the same to both sides, ie Take c from both sides, not take from one and add to the other
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    (Original post by jermaindefoe)
    please could someone check my rearranging for this

    i really suck at these and i did this from just looking at a guide so i havent really learnt it :s

    y = mx + c (make x the subject)
    y + c = mx
    U did wrongly.

    It's y-c = mx
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    (Original post by SimonM)
    When you do something you have to do the same to both sides, ie Take c from both sides, not take from one and add to the other
    Exactly.

    Like,
    y = mx + c
    y - c = mx + c - c
    • Thread Starter
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    that was a silly mistake, so my answer is right, just i forgot to put a minus?

    so x = y-c/m
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    Yes
    • Thread Starter
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    so for

    (ex)/d - g = f
    (ex/d) = g + f
    ex = d(g+f)
    x = [d(g+f)]/2
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    Assuming e = 2
    • Thread Starter
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    lol sorry about that - that was a typo

    everything over E not 2

    so if thats right it is time to

    :party:
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    (Original post by jermaindefoe)
    so for

    (ex)/d - g = f
    (ex/d) = g + f
    ex = d(g+f)
    x = [d(g+f)]/2
    x=\frac{d(g+f)}{e}

    Yep, that's right. Just a typo in the last line, I think - you put /2 not /e.
 
 
 
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