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#1
Could someone help with this question please
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#2
This is the question
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1 week ago
#3
It gives you the y intercept, and you know it's a negative quadratic. You're also given the turning point, so can differentiate and set to zero to find a in terms of b, or vice versa, and then you can sub that back into the original equation for the curve and use the point (2,3) that they've given you to form an equation to solve for a and b.
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1 week ago
#4
(Original post by gaminghoodwink)
Could someone help with this question please
What are your thoughts so far? What will the y-intercept be? How does knowing the turning point (2,3) help you?
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#5
(Original post by laurawatt)
What are your thoughts so far? What will the y-intercept be? How does knowing the turning point (2,3) help you?
so the y-intercept is -5 and that is the value of the c. Then I can do completing the square in order to get the remaining values
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1 week ago
#6
(Original post by gaminghoodwink)
so the y-intercept is -5 and that is the value of the c. Then I can do completing the square in order to get the remaining values
Yep
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