confused on A2 chem acid/base question

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interlanken-fall
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why for both of this equation the conc on H+ so high? shouldn't it be low as a base if being reacted
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Hellllpppp
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Is there supposed to be an attachment?
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interlanken-fall
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(Original post by Hellllpppp)
Is there supposed to be an attachment?
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interlanken-fall
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this is the attachment
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Pigster
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(Original post by interlanken-fall)
why for both of this equation the conc on H+ so high? shouldn't it be low as a base if being reacted
I wouldn't describe 1 x 10^-14 or 5 x 10^-13 as particularly high.
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interlanken-fall
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(Original post by Pigster)
I wouldn't describe 1 x 10^-14 or 5 x 10^-13 as particularly high.
i think i get it, we find the (H) conc and by this we find the pH, why would there by any H thought eg NaOH= Na+ and OH- no H
can you help with this question
https://www.thestudentroom.co.uk/sho....php?t=7041575
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interlanken-fall
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(Original post by Pigster)
I wouldn't describe 1 x 10^-14 or 5 x 10^-13 as particularly high.
wait wouldnt it be [H] = [OH] since they reach equilibrium?
edit nvm its a strong base
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deskochan
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I try to understand what you get confused and I think you ask why the equilibrium does not look like balance in the concentrated alkali solution. Tell me if I misunderstand your confusing point.
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deskochan
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I continue now. For the equilibrium, in this case, H+ +OH- <--> H2O, [H+][OH-] = 10^-14. When concentrated alkali added, [OH-] > [H+] but they multiply together also equal to 10^-14, that is equilibrium is still established (by Le Chatelier's Principle). That is pH >7 when it is in an alkali medium and equilibrium to be achieved.
The second I think to be the perception of chemistry and mathematics inconsistency. pH = -log[H+]. I show the diagram the relationship between pH value and [H+] and it shows the property of log curve and lower [H+], the higher pH value, and consistency in the mathematics and chemistry concept.
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