Flanno2004
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Hey could you please help me I have absolutely no idea how to answer this question it makes no sense. I’ve figured out the first bullet point, I just don’t know how to do the second one.
Thanks in advance.
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casualchemistry
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(Original post by Flanno2004)
Hey could you please help me I have absolutely no idea how to answer this question it makes no sense. I’ve figured out the first bullet point, I just don’t know how to do the second one.
Thanks in advance.
The starting material is an alcohol - that stretching frequency is classic for an O-H bond.

On oxidation, it depends on whether the alcohol is primary or secondary.

If a primary alcohol, you'd expect full oxidation to give the carboxylic acid. In the IR spectrum, you'd see a peak of around 1730cm-1 for the C=O double bond but also keep the 3300ish cm-1 peak for the O-H - although now it would be a big broad V-shape due to the more extensive hydrogen bonding that is possible for the carboxylic acid.

If a secondary alcohol, you'd expect a ketone to form with an IR stretching frequency of about 1715cm-1.

[Note: a tertiary alcohol can't be oxidised]
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