# Algebra

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#1
Thank you all
Last edited by Davies96; 1 month ago
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1 month ago
#2
x^3-x-10=0
when x=2 and x=3
substitute 2 into the equation 2^3-2-10
= -4
when x=3
x^3-x-10
substitute 3^3-3-10
18-3-10= 15-10= 5
-4,5
there is a change in sign, there is a solution between 2 and 3.
0
1 month ago
#3
solution
x^3-x-10=0
x=2 and x=3
when x= 2 2^3-2-10=-4
when x=3
substitute x^3-x-10
3^3-3-10=5
-4,5
there is a change in sign,the solution is between 2 and 3
0
1 month ago
#4
I can assist.
0
1 month ago
#5
(Original post by Davies96)
Hi there, does any one know how to work out the following:
A solution to the equation x(to power of three) -x -10 =0 lies between 2 and 3. Use a trail and improvement method to find the solution to 1 decimal Place
You must have covered some form of interval reduction or bisection where you find the sign of the two end points and then evaulate the function in the "middle". The root will occur in the sub (half) interval which contains a sign change. Then repeat until you get the desired accuracy.
Last edited by mqb2766; 1 month ago
0
1 month ago
#6
(Original post by techsnowy)
solution
Please edit / remove your posts - it is against forum rules to post solutions
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