helpplease346
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I am confused to part a) and part b). Please help. How do you do this?
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helpplease346
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(Original post by helpplease346)
I am confused to part a) and part b). Please help. How do you do this?
http://prntscr.com/16836q3 there is the question
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HaydenFordz
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Ok let me try to work this out on paper -- what part of it don't you understand?

(Original post by helpplease346)
I am confused to part a) and part b). Please help. How do you do this?
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helpplease346
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(Original post by HaydenFordz)
Ok let me try to work this out on paper -- what part of it don't you understand?
Part a).
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Nighthawk64
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part a)
Use simultaneous equations:
250=300a+b
410=700a+b
Then solve for a and b.

part b)
I like to think about it by imaging if the article is 0 words which gives you the initial fixed fee
If you imagine F = aw + b as a straight line, a is the gradient which is defined when you increase x (in this case w) which is the extra fee per word.

Hope this makes sense
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helpplease346
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(Original post by Nighthawk64)
part a)
Use simultaneous equations:
250=300a+b
410=700a+b
Then solve for a and b.

part b)
I like to think about it by imaging if the article is 0 words which gives you the initial fixed fee
If you imagine F = aw + b as a straight line, a is the gradient which is defined when you increase x (in this case w) which is the extra fee per word.

Hope this makes sense
Thank you very much
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HaydenFordz
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(Original post by Nighthawk64)
part a)
Use simultaneous equations:
250=300a+b
410=700a+b
Then solve for a and b.

part b)
I like to think about it by imaging if the article is 0 words which gives you the initial fixed fee
If you imagine F = aw + b as a straight line, a is the gradient which is defined when you increase x (in this case w) which is the extra fee per word.

Hope this makes sense
tbh I have spent this time tryna do the simultaneous equations -- and I keep somehow getting it wrong
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Nighthawk64
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(Original post by HaydenFordz)
tbh I have spent this time tryna do the simultaneous equations -- and I keep somehow getting it wrong
If you subtract Eq1 from Eq2:
410=700a+b
250=300a+b
160=400a
=> a = 2/5

410=700(2/5)+b
410=280+b
=> b = 130

In case you were interested
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HaydenFordz
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(Original post by Nighthawk64)
If you subtract Eq1 from Eq2:
410=700a+b
250=300a+b
160=400a
=> a = 2/5

410=700(2/5)+b
410=280+b
=> b = 130

In case you were interested
thank you very much -- I somehow worked out the fee to be 176.33 I think lmfao
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