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#1
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1 month ago
#2
= 13/52 + 13/52 (13 cards in suit, 52 cards in a set)
= 26/52 = 1/2
b) P(Black Ace or Heart) = P(Black Ace) + P(Heart)
= 1/52 + 13/52
= 14/52 = 7/26

Hope this helps
0
#3
(Original post by Nighthawk64)
= 13/52 + 13/52 (13 cards in suit, 52 cards in a set)
= 26/52 = 1/2
b) P(Black Ace or Heart) = P(Black Ace) + P(Heart)
= 1/52 + 13/52
= 14/52 = 7/26

Hope this helps
How were you able to get the P(Black ace) as 1/52?
0
1 month ago
#4
(Original post by Okra124)
How were you able to get the P(Black ace) as 1/52?
There is 1 black ace in a pack of cards. There are 52 cards in a pack. So there is a chance of 1/52 to get a black ace.

Does this help?
0
1 month ago
#5
(Original post by Nighthawk64)
There is 1 black ace in a pack of cards. There are 52 cards in a pack. So there is a chance of 1/52 to get a black ace.

Does this help?
There are two black aces, the ace of clubs and the ace of spades.
0
1 month ago
#6
(Original post by Plücker)
There are two black aces, the ace of clubs and the ace of spades.
Oof, I was being stupid, I am sorry, I was just thinking of ace of spades!
1
#7
Thanks so much! It makes a lot of sense now 😃😃
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