# Logs help

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#1
Wasn't able to do last question and not sure if it relates to coordinates I got from these questions
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1 month ago
#2
what questions?
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#3
last question sir
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1 month ago
#4
(Original post by dwrfwrw)
last question sir
imma miss
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#5
(Original post by Book0306)
imma miss
think i know how to do it i think you use distance formula and using coordinates of (c,log2(c), (c,log2(c-3) and using distance being equal to 4 and solve
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1 month ago
#6
(Original post by dwrfwrw)
think i know how to do it i think you use distance formula and using coordinates of (c,log2(c), (c,log2(c-3) and using distance being equal to 4 and solve
cool
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#7

(Original post by Book0306)
cool
do u understand lol
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1 month ago
#8
(Original post by dwrfwrw)

do u understand lol
haha nope
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#9
(Original post by Book0306)
haha nope
Ok, so since P has equation of y=log2(x) and the x coordinate of P is C , we sub c into y=log2(c) to get coordinate of P which is (C,LOG2(C),
NOW FOR Q, since Q has x coordinate of c, and has equation of y=log2(x-3), we sub c in to get y and we get (c, log2(c-3))
they said the distance is 4 and we find distance between those two points using the distance formula and then solve for c 0
1 month ago
#10
(Original post by dwrfwrw)
Ok, so since P has equation of y=log2(x) and the x coordinate of P is C , we sub c into y=log2(c) to get coordinate of P which is (C,LOG2(C),
NOW FOR Q, since Q has x coordinate of c, and has equation of y=log2(x-3), we sub c in to get y and we get (c, log2(c-3))
they said the distance is 4 and we find distance between those two points using the distance formula and then solve for c can u pm quick?
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1 month ago
#11
A rough sketch would help. Both points have x=c as the x coordinate, so the distance is simply the vertical distance, so the difference of two logs ...?
(Original post by dwrfwrw)
Ok, so since P has equation of y=log2(x) and the x coordinate of P is C , we sub c into y=log2(c) to get coordinate of P which is (C,LOG2(C),
NOW FOR Q, since Q has x coordinate of c, and has equation of y=log2(x-3), we sub c in to get y and we get (c, log2(c-3))
they said the distance is 4 and we find distance between those two points using the distance formula and then solve for c Last edited by mqb2766; 1 month ago
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#12
(Original post by mqb2766)
A rough sketch would help. Both points have x=c as the x coordinate, so the distance is simply the vertical distance, so the difference of two logs ...?
yeah i mean i didnt need to sketch the diagram, it was already given to us i was just overcomplicating the question, thanks for helping though
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