The Student Room Group

Circle theorems

How would you do part b of this question? for part a I got 58° but I can't figure out part bScreenshot_20210622_204936.jpg
(edited 2 years ago)
What have you tried?
The "angles in the same segment" theorem means that <CAB = <BDC.
<ADB + <BDC = <ADC (which you worked out in part a)

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