# projectile motion

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Thread starter 1 month ago
#1
a ball is hit when it is at a height of 0.400m. it just clears the tennis net, travelling horrizontally and then lands on the ground at a distance of 11.9m from the net.
(a) show that the horizontal component of velocity of the ball is about 30ms

i just simply dont know what to do
Last edited by Mustafah41352; 1 month ago
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1 month ago
#2
(Original post by Mustafah41352)
a ball is hit when it is at a height of 0.400m. it just clears the tennis net, travelling horrizontally and then lands on the ground at a distance of 11.9m from the net.
(a) show that the horizontal component of velocity of the ball is about 30ms

i just simply dont know what to do
Use SUVAT and the information ....

You need to attempt the question before we can help
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Thread starter 1 month ago
#3
(Original post by Muttley79)
Use SUVAT and the information ....

You need to attempt the question before we can help
i dont know where to start.
the most i can do is S=11.9 U=0 a=9.8. im dont really understant at all.
Last edited by Mustafah41352; 1 month ago
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1 month ago
#4
(Original post by Mustafah41352)
i dont know where to start.
the most i can do is S=11.9 U=0 a=0. im dont really understant at all.
And vertically?
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Thread starter 1 month ago
#5
(Original post by Muttley79)
And vertically?
so vertically would be 0.91-0.4=0.51
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1 month ago
#6
(Original post by Mustafah41352)
so vertically would be 0.91-0.4=0.51
Why is u= 0 btw?

Where do these numbers come from? What is u and a ?
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1 month ago
#7
(Original post by Muttley79)
Why is u= 0 btw?

Where do these numbers come from? What is u and a ?
i guess they are assuming the value of a and u.well shouldn't we use Fcostheta to find the horizontal component?
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Thread starter 1 month ago
#8
(Original post by Muttley79)
Why is u= 0 btw?

Where do these numbers come from? What is u and a ?
u is initial velocity, but i dont know how to get that, and a is acceleration but since im finding the horizontal it is 0?
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1 month ago
#9
(Original post by Fareeha18)
i guess they are assuming the value of a and u.well shouldn't we use Fcostheta to find the horizontal component?
We only need to show the horiz component 'is about 30' so I would just call it 'u'
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1 month ago
#10
(Original post by Mustafah41352)
u is initial velocity, but i dont know how to get that, and a is acceleration but since im finding the horizontal it is 0?
I've done the question - have you now?
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Thread starter 1 month ago
#11
(Original post by Muttley79)
I've done the question - have you now?
i think so, so S=0.91 U=0 a=9.8 put into s=ut+1/2 a t^2 t=0.43 then v=d/t to get 27.
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