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Infinity in integration
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Eris13696
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#1
Hello everyone, I hope you’re having a great day.
I wanted to ask about infinity. When do I know if the infinity will make the integral =0? Because all I understand if the number is trying to approach a 0 then we can make it a 0. I hope someone can clear my confusion about it. Like in this question how is it approaching 0?
I wanted to ask about infinity. When do I know if the infinity will make the integral =0? Because all I understand if the number is trying to approach a 0 then we can make it a 0. I hope someone can clear my confusion about it. Like in this question how is it approaching 0?
Last edited by Eris13696; 1 year ago
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Shaqiloheal
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#2
(Original post by Eris13696)
Hello everyone, I hope you’re having a great day.
I wanted to ask about infinity. When do I know if the infinity will make the integral =0? Because all I understand if the number is trying to approach a 0 then we can make it a 0. I hope someone can clear my confusion about it. Like in this question how is it approaching 0?
Hello everyone, I hope you’re having a great day.
I wanted to ask about infinity. When do I know if the infinity will make the integral =0? Because all I understand if the number is trying to approach a 0 then we can make it a 0. I hope someone can clear my confusion about it. Like in this question how is it approaching 0?
u -> -infinity (e^u) = 0
This is proven by applying the limit property
Lim_x -> -infinity (2x+3)
a=2 n=1
= -infinity
Therefore 1/2 * 0 = 0
The limit as x approaches zero would be negative infinity, since the graph goes down forever as you approach zero from either side: As a general rule, when you are taking a limit and the denominator equals zero, the limit will go to infinity or negative infinity.
Hope this helps. Sorry I did this on my phone.
By any chance are you a pure/applied mathematics student?
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Eris13696
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#3
(Original post by Shaqiloheal)
By applying the common limit:
u -> -infinity (e^u) = 0
This is proven by applying the limit property
Lim_x -> -infinity (2x+3)
a=2 n=1
= -infinity
Therefore 1/2 * 0 = 0
The limit as x approaches zero would be negative infinity, since the graph goes down forever as you approach zero from either side: As a general rule, when you are taking a limit and the denominator equals zero, the limit will go to infinity or negative infinity.
Hope this helps. Sorry I did this on my phone.
By any chance are you a pure/applied mathematics student?
By applying the common limit:
u -> -infinity (e^u) = 0
This is proven by applying the limit property
Lim_x -> -infinity (2x+3)
a=2 n=1
= -infinity
Therefore 1/2 * 0 = 0
The limit as x approaches zero would be negative infinity, since the graph goes down forever as you approach zero from either side: As a general rule, when you are taking a limit and the denominator equals zero, the limit will go to infinity or negative infinity.
Hope this helps. Sorry I did this on my phone.
By any chance are you a pure/applied mathematics student?
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Shaqiloheal
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#4
(Original post by Eris13696)
Thank you for your reply, unfortunately I haven’t been introduced to the limit properties or the common limit, so is there a good video that can summarize them so I can understand it. So when I see -infinity I will assume directly it’s equal to 0? yes, I’m studying pure math.
Thank you for your reply, unfortunately I haven’t been introduced to the limit properties or the common limit, so is there a good video that can summarize them so I can understand it. So when I see -infinity I will assume directly it’s equal to 0? yes, I’m studying pure math.
Nice im away to start my 1st year in Applied Mathematics at University of Abedeen. I just finished my HNC in Electrical Engineering but fell in love with mathematics. I have experience withe intergral and differential calculus through Engineering Mathematics 2 which was my final unit therefore definate intergrals are fresh in my head.
Which uni are you at?
Last edited by Shaqiloheal; 1 year ago
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Eris13696
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#5
(Original post by Shaqiloheal)
Its much easier to explain the concept with a graph. The aysmptore of the line would be going down the negative end of the y axis to zero infinately. Thats the best way to explain it.
Nice im away to start my 1st year in Applied Mathematics at University of Abedeen. I just finished my HNC in Electrical Engineering but fell in love with mathematics. I have experience withe intergral and differential calculus through Engineering Mathematics 2 which was my final unit therefore definate intergrals are fresh in my head.
Which uni are you at?
Its much easier to explain the concept with a graph. The aysmptore of the line would be going down the negative end of the y axis to zero infinately. Thats the best way to explain it.
Nice im away to start my 1st year in Applied Mathematics at University of Abedeen. I just finished my HNC in Electrical Engineering but fell in love with mathematics. I have experience withe intergral and differential calculus through Engineering Mathematics 2 which was my final unit therefore definate intergrals are fresh in my head.
Which uni are you at?
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RDKGames
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#6
(Original post by Eris13696)
Hello everyone, I hope you’re having a great day.
I wanted to ask about infinity. When do I know if the infinity will make the integral =0? Because all I understand if the number is trying to approach a 0 then we can make it a 0. I hope someone can clear my confusion about it. Like in this question how is it approaching 0?
Hello everyone, I hope you’re having a great day.
I wanted to ask about infinity. When do I know if the infinity will make the integral =0? Because all I understand if the number is trying to approach a 0 then we can make it a 0. I hope someone can clear my confusion about it. Like in this question how is it approaching 0?
So then what happens to the exponential function as its argument goes to -infinity? It decays to 0.
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