Daisiee
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Hi ^^ Can you help with this. I do not know whether it is an error in the book but try solving these two simultaneously please:
x^2 + y^2 + 8x - 2y - 3 =0
x - 2y - 12 =0
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mqb2766
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(Original post by Daisiee)
Hi ^^ Can you help with this. I do not know whether it is an error in the book but try solving these two simultaneously please:
x^2 + y^2 + 8x - 2y - 3 =0
x - 2y - 12 =0
If you factorize the quadratic into a circle, or plot both curves in desmos, its fairly clear they dont intersect.
If there is a solution in the textbook, maybe post it as well as there may be a typo error in one of the equatoins.
Last edited by mqb2766; 2 months ago
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Daisiee
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(Original post by mqb2766)
If you factorize the quadratic into a circle, or plot both curves in desmos, its fairly clear they dont intersect.
If there is a solution in the textbook, maybe post it as well as there may be a typo error in one of the equatoins.
The answers in the book are x=6 and y=-3
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mqb2766
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(Original post by Daisiee)
The answers in the book are x=6 and y=-3
What is the full question as that refers to a single point. You'd normally expect two points when a line intersects a circle. It is a tangent point?
Note that llies on the line, but not the circle.
Last edited by mqb2766; 2 months ago
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old_engineer
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(Original post by Daisiee)
The answers in the book are x=6 and y=-3
The question would yield that answer if the circle equation contained -8x rather than +8x.
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