Mil_Jeans
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#1
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So, guys, the question is an MCQ. Something todo with moles, i'm not sure. here it is:

The equation for decompositon of magnesium nitrate is shown:

2Mg(NO3)2(s) = 2MgO(s) + 4NO2(g) + O2(g)

Which volume of gas is produced when 0.1 moles of magnesium nitrate is decomposed completely?

A. 1.2dm^3
B. 4.8dm^3
C. 6.0dm^3
D. 8.4dm^3
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AzureWind
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Why the bloody hell are you trying to do maths at 2:40 on a Saturday?
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scimus63
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if its at 24 celsius then I think the answer is c.
0.1 moles of magnesium nitrate will produce 0.2 moles of NO2, which occupies 24 x 0.2 = 4.8 dm3
0.1 moles of magnesium nitrate will produce 0.05 moles of oxygen, which occupies 24 x 0.05 = 1.2 dm3

so total volume is 6dm3 at 24 celsius
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scimus63
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look here it may help a bit:

https://www.science-revision.co.uk/moles_and_gases.html
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