Can't get this question right!!!Watch
The equation for decompositon of magnesium nitrate is shown:
2Mg(NO3)2(s) = 2MgO(s) + 4NO2(g) + O2(g)
Which volume of gas is produced when 0.1 moles of magnesium nitrate is decomposed completely?
0.1 moles of magnesium nitrate will produce 0.2 moles of NO2, which occupies 24 x 0.2 = 4.8 dm3
0.1 moles of magnesium nitrate will produce 0.05 moles of oxygen, which occupies 24 x 0.05 = 1.2 dm3
so total volume is 6dm3 at 24 celsius