# Hyperbolic

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Given that:

sinh x + sinh y = 25/12

cosh x - cosh y = 5/12

show that:

2e^x=5+2e^-y

and

3e^-x=5+3e^y

Hence find the real values of x and y (x=ln 3, y=ln 2)

sinh x + sinh y = 25/12

cosh x - cosh y = 5/12

show that:

2e^x=5+2e^-y

and

3e^-x=5+3e^y

Hence find the real values of x and y (x=ln 3, y=ln 2)

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#2

Try using the define of sinh and cosh to rewrite all the terms. Then use a method similar to how you would solve simultaneous equations to get your two desired equations

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I know all of that. Second step (simultaneous equation is a joke) But first step (transformation) is pretty hard. I have got at least 100 "help" like that. Can you be more specific? Or simply say I do not know!

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#4

(Original post by

I know all of that. Second step (simultaneous equation is a joke) But first step (transformation) is pretty hard. I have got at least 100 "help" like that. Can you be more specific? Or simply say I do not know!

**Hillsby**)I know all of that. Second step (simultaneous equation is a joke) But first step (transformation) is pretty hard. I have got at least 100 "help" like that. Can you be more specific? Or simply say I do not know!

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I am struggling with this part:

Given that:

sinh x + sinh y = 25/12

cosh x - cosh y = 5/12

show that:

2e^x=5+2e^-y

and

3e^-x=5+3e^y

Can you solve simultaneous equation are easy. I meant that basic equations like sinh =(e^x-e^-x)/2 are not helpful, but full working. You can try identities and multiplication by e^x. Q is the part of the most difficult Qs of A-level and uni. If you ask, they usually turn to quadratic hyperbolic or double angle hyperbolic.Anyway, thank you for interest

Given that:

sinh x + sinh y = 25/12

cosh x - cosh y = 5/12

show that:

2e^x=5+2e^-y

and

3e^-x=5+3e^y

Can you solve simultaneous equation are easy. I meant that basic equations like sinh =(e^x-e^-x)/2 are not helpful, but full working. You can try identities and multiplication by e^x. Q is the part of the most difficult Qs of A-level and uni. If you ask, they usually turn to quadratic hyperbolic or double angle hyperbolic.Anyway, thank you for interest

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#6

(Original post by

I am struggling with this part:

Given that:

sinh x + sinh y = 25/12

cosh x - cosh y = 5/12

show that:

2e^x=5+2e^-y

and

3e^-x=5+3e^y

Can you solve simultaneous equation are easy. I meant that basic equations like sinh =(e^x-e^-x)/2 are not helpful, but full working. You can try identities and multiplication by e^x. Q is the part of the most difficult Qs of A-level and uni. If you ask, they usually turn to quadratic hyperbolic or double angle hyperbolic.Anyway, thank you for interest

**Hillsby**)I am struggling with this part:

Given that:

sinh x + sinh y = 25/12

cosh x - cosh y = 5/12

show that:

2e^x=5+2e^-y

and

3e^-x=5+3e^y

Can you solve simultaneous equation are easy. I meant that basic equations like sinh =(e^x-e^-x)/2 are not helpful, but full working. You can try identities and multiplication by e^x. Q is the part of the most difficult Qs of A-level and uni. If you ask, they usually turn to quadratic hyperbolic or double angle hyperbolic.Anyway, thank you for interest

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(Original post by

You don't need to manipulate each expression past turning sinh and cosh into their respective exponential counterparts. All you have to do afterwards is add/subtract the 2 equations to get the desired result. Why would you change the expressions anymore than that if the answer they want is of the form e^x, e^-x, e^y, e^-y? If that's not what you're asking for help with then please be more clear.

**JustSomeGuy:/**)You don't need to manipulate each expression past turning sinh and cosh into their respective exponential counterparts. All you have to do afterwards is add/subtract the 2 equations to get the desired result. Why would you change the expressions anymore than that if the answer they want is of the form e^x, e^-x, e^y, e^-y? If that's not what you're asking for help with then please be more clear.

2. you have to find x, y.

to find only x, y is marked 50% or E (see bellow)

Is it clear now?

Given that:

sinh x + sinh y = 25/12

cosh x - cosh y = 5/12

show that:

2e^x=5+2e^-y

and

3e^-x=5+3e^y

Hence find x and y

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#8

(Original post by

I copied full question for you: 1. You have to prove as showed

2. you have to find x, y.

to find only x, y is marked 50% or E (see bellow)

Is it clear now?

Given that:

sinh x + sinh y = 25/12

cosh x - cosh y = 5/12

show that:

2e^x=5+2e^-y

and

3e^-x=5+3e^y

Hence find x and y

**Hillsby**)I copied full question for you: 1. You have to prove as showed

2. you have to find x, y.

to find only x, y is marked 50% or E (see bellow)

Is it clear now?

Given that:

sinh x + sinh y = 25/12

cosh x - cosh y = 5/12

show that:

2e^x=5+2e^-y

and

3e^-x=5+3e^y

Hence find x and y

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reply

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#9

**Hillsby**)

I copied full question for you: 1. You have to prove as showed

2. you have to find x, y.

to find only x, y is marked 50% or E (see bellow)

Is it clear now?

Given that:

sinh x + sinh y = 25/12

cosh x - cosh y = 5/12

show that:

2e^x=5+2e^-y

and

3e^-x=5+3e^y

Hence find x and y

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reply

(Original post by

The question was already clear. What I meant was it's not clear what part you're struggling with.

**JustSomeGuy:/**)The question was already clear. What I meant was it's not clear what part you're struggling with.

(Original post by

Have you even attempted the problem?

**tej3141**)Have you even attempted the problem?

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#11

(Original post by

So, do you think you ca solve it

O ye, cannot solve it (first part). Find x and y is not problem

**Hillsby**)So, do you think you ca solve it

O ye, cannot solve it (first part). Find x and y is not problem

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#12

**Hillsby**)

So, do you think you ca solve it

O ye, cannot solve it (first part). Find x and y is not problem

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#13

(Original post by

How did you find x and y without answering answering first part?

**tej3141**)How did you find x and y without answering answering first part?

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#14

(Original post by

Most likely used the equations that he was supposed to prove existed from part a.

**JustSomeGuy:/**)Most likely used the equations that he was supposed to prove existed from part a.

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(Original post by

I already tried and solved it beforehand. As I said before, all you do is convert both equations into their exponential forms (nothing more) and then you add the 2 equations together for one of the answers and subtract them for the other (as I had already stated in the previous post).

**JustSomeGuy:/**)I already tried and solved it beforehand. As I said before, all you do is convert both equations into their exponential forms (nothing more) and then you add the 2 equations together for one of the answers and subtract them for the other (as I had already stated in the previous post).

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#16

(Original post by

Show me your working! Convert both equations into their exponential form, stated in the task.

**Hillsby**)Show me your working! Convert both equations into their exponential form, stated in the task.

Also sorry the pics sideways, just tilt your head .

Last edited by JustSomeGuy:/; 1 month ago

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(Original post by

Perform 1+2 for one equation and 1-2 for the other. What about it do you find difficult? You're just using the properties of sinh and cosh and then doing some simultaneous equations which you said was easy in your first post. Anywhere hope this clears things up...

Also sorry the pics sideways, just tilt your head .

**JustSomeGuy:/**)Perform 1+2 for one equation and 1-2 for the other. What about it do you find difficult? You're just using the properties of sinh and cosh and then doing some simultaneous equations which you said was easy in your first post. Anywhere hope this clears things up...

Also sorry the pics sideways, just tilt your head .

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#18

(Original post by

A good start, but what next? Remember, you have to get second pair of equation exactly it is given. Good luck! you can use substitution anytime if you are not sure.

**Hillsby**)A good start, but what next? Remember, you have to get second pair of equation exactly it is given. Good luck! you can use substitution anytime if you are not sure.

Last edited by Interea; 1 month ago

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#19

Yeah I'm quite confused why the one who's asking for help is trying to give hints here

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(Original post by

They've already told you exactly how to do it multiple times - are you still stuck? People aren't meant to share full solutions in the study help forums by the way, hence why they're giving you hints instead of just giving you the answer

**Interea**)They've already told you exactly how to do it multiple times - are you still stuck? People aren't meant to share full solutions in the study help forums by the way, hence why they're giving you hints instead of just giving you the answer

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