University CHEMISTRY HELP NEEDED
You have a stock bottle of copper sulphate (heptahydrate)
If the relative molecular mass (Mr) of copper sulphate (heptahydrate) is 249.68, what is the molar concentration of the solution? Show your calculations and provide units.
Below is the mass concentration (%w/v) and volume of copper sulphate solution to be prepared.
Prepare 50ml of 20% w/v copper sulphate
If the relative molecular mass (Mr) of copper sulphate (heptahydrate) is 249.68, what is the molar concentration of the solution? Show your calculations and provide units.
Below is the mass concentration (%w/v) and volume of copper sulphate solution to be prepared.
Prepare 50ml of 20% w/v copper sulphate
The equation to get molar concentration is... concentration = (moles x 1000) / volume. The x 1000 bit is there because your given volume is in ml, which is basically cm^3, whilst the unit for concentration is mol/dm^3.
You know the volume, 50 ml, but don't know the number of moles so you first need to use the equation... moles = mass / relative molecular mass.
You're given the relative molecular mass, 249.68 g/mol, and at first glance it seems you don't know the mass, but you do. The concentration is 20% w/v which means weight per volume. So the mass in grams is 20 % of the volume in millilitres. The mass is therefore 20 % of 50, which is 10 g.
You now have all the numbers you need to plug into the two equations. Think you can do it now?
You know the volume, 50 ml, but don't know the number of moles so you first need to use the equation... moles = mass / relative molecular mass.
You're given the relative molecular mass, 249.68 g/mol, and at first glance it seems you don't know the mass, but you do. The concentration is 20% w/v which means weight per volume. So the mass in grams is 20 % of the volume in millilitres. The mass is therefore 20 % of 50, which is 10 g.
You now have all the numbers you need to plug into the two equations. Think you can do it now?
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