Back
to top
help pls
Watch this threadPage 1 of 1
Go to first unread
Skip to page:
boba123456789
Badges:
2
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#1
Hi can someone please help me with this question- thanks in advance.
‘Hex-1-ene is a liquid with a BP of 63 degrees and density of 0.67 gcm-3
Hex-1-ene can be prepared by refluxing hexan-1-Ol (BP 157 degrees) with an acid catalyst.
Hexan-1-ol is a liquid with a density of 0.82gcm-3
after reflux , the resulting mixture contains unreacted hexan-1-ol, hex-1-ene and water. The mixture is then purified.
The expected percentage yield of hex-1-ene from hexan1-ol is 62.5%
A student plans to prepare 4.20g of hex-1ene by this method.
Calculate the mass of Hexan-1-ol that the student should use and explain how you could obtain pure hex-1-ene from the mixture obtained after relfux.
‘Hex-1-ene is a liquid with a BP of 63 degrees and density of 0.67 gcm-3
Hex-1-ene can be prepared by refluxing hexan-1-Ol (BP 157 degrees) with an acid catalyst.
Hexan-1-ol is a liquid with a density of 0.82gcm-3
after reflux , the resulting mixture contains unreacted hexan-1-ol, hex-1-ene and water. The mixture is then purified.
The expected percentage yield of hex-1-ene from hexan1-ol is 62.5%
A student plans to prepare 4.20g of hex-1ene by this method.
Calculate the mass of Hexan-1-ol that the student should use and explain how you could obtain pure hex-1-ene from the mixture obtained after relfux.
0
reply
scimus63
Badges:
9
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#2
Report
#2
I think you need to just scale up the amount of alcohol needed by 100/62.5 = 1.6. to take account of loss due to yield of 62.5, so use 4.2g x 16 = 6.72g.
The alcohol and the alkene will not mix, the water might not even dissolve the alcohol that well since it contains a fairly large "organic" portion to the molecule. However they all have different densities and two of the three at least wont mix, so just use a separating funnel to get the alkene out then dry it with some calcium sulfate.
The alcohol and the alkene will not mix, the water might not even dissolve the alcohol that well since it contains a fairly large "organic" portion to the molecule. However they all have different densities and two of the three at least wont mix, so just use a separating funnel to get the alkene out then dry it with some calcium sulfate.
0
reply
boba123456789
Badges:
2
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#3
(Original post by scimus63)
I think you need to just scale up the amount of alcohol needed by 100/62.5 = 1.6. to take account of loss due to yield of 62.5, so use 4.2g x 16 = 6.72g.
The alcohol and the alkene will not mix, the water might not even dissolve the alcohol that well since it contains a fairly large "organic" portion to the molecule. However they all have different densities and two of the three at least wont mix, so just use a separating funnel to get the alkene out then dry it with some calcium sulfate.
I think you need to just scale up the amount of alcohol needed by 100/62.5 = 1.6. to take account of loss due to yield of 62.5, so use 4.2g x 16 = 6.72g.
The alcohol and the alkene will not mix, the water might not even dissolve the alcohol that well since it contains a fairly large "organic" portion to the molecule. However they all have different densities and two of the three at least wont mix, so just use a separating funnel to get the alkene out then dry it with some calcium sulfate.
0
reply
X
Page 1 of 1
Go to first unread
Skip to page:
Quick Reply
