Trig doubt Watch

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Jorge
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#1
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The book has a s a solution for 0<=A<=180

sinA = 0 > A = 90º

Surely that is wrong. Or is it my brain that's seized up altogether?

sinA = 0 > A = 0

And so i think the answer within the range should be 0º and not 90º

Help...

jorge
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Aitch
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(Original post by Jorge)
The book has as a solution for 0<=A<=180

sinA = 0 > A = 90º

Surely that is wrong. Or is it my brain that's seized up altogether?

sinA = 0 > A = 0

And so i think the answer within the range should be 0º and not 90º

Help...

jorge
I don't think I have the question grasped correctly! Can you type it in verbatim?

Aitch
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Aitch
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...and the given answer?

Aitch
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Jorge
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#4
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(Original post by Aitch)
I don't think I have the question grasped correctly! Can you type it in verbatim?

Aitch

It's not so much the question itself. It's the answer.

If you end up with sinA = 0

what is the value of A between 0º and 180º.

The book says 90º!


jorge
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Aitch
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(Original post by Jorge)
It's not so much the question itself. It's the answer.

If you end up with sinA = 0

what is the value of A between 0º and 180º.

The book says 90º!


jorge
Nope

0 or 180

Aitch
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Aitch
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(Original post by Aitch)
Nope

0 or 180

Aitch
Are you sure sure sure you haven't got a sin for a cos somewhere?

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davidreesjones
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have you tried substituting their answer into the start to see if the working has gone wrong
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Jorge
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(Original post by Aitch)
Are you sure sure sure you haven't got a sin for a cos somewhere?

Aitch
I am not talking about my workings or answer.

It is the book itself that came up with the answer


sinA = 0 > A = 90º
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Aitch
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(Original post by Jorge)
I am not talking about my workings or answer.

It is the book itself that came up with the answer
Ah!

I'm with you now. I hadn't realised that this bit was a direct quote.

Aitch
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Jorge
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#10
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#10
Therefore ?....

The book is wrong. Right?

jorge
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