Biochempsych12
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Difference between 5th and 6th ionisation energy of phosphorus. Would it just be that as there is no change in shell the nuclear charge of the positive ion I only slightly increases with each electron lost, therefore the ionisation energy only slightly increases
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bl0bf1sh
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Successive ionisation energies increase, as electrons are being removed from an increasingly positive ion, so electrostatic attraction between the nucleus and the remaining electrons increases.
A large increase in IE represents a change in shell. Electrons are removed from the outer shell first (which is the furthest from the nucleus, so experiences the weakest attraction). At the point when the next electron to be removed is the first from a shell which is closer to the nucleus, the nuclear attraction is much greater, so the IE becomes much larger.

If we look at the successive ionisation energies for phosphorus, we see that the 6th is quite a lot larger than the 5th. So the 6th electron being removed is in a shell that is closer to the nucleus than the 5th.

Nuclear charge stays the same because the number of protons stays the same.
The 6th electron being removed is closer to the nucleus, and experiences less shielding from other electrons, so the electrostatic attraction between the nucleus and this 6th electron is much greater than that between the 5th electron and the nucleus, so lots more energy is required to overcome this greater electrostatic attraction.
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