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chemistry help

3.528 g of a Group 2 metal, M, is reacted with an excess of chlorine.
The reaction forms 9.775g of a chloride.

What is metal M?
Does anyone know what I need to do to get the answer?

Reply 1

I suggest first writing an equation to keep track of what’s going on. Work out the mass and moles of Cl in the reaction. Use moles of Cl to get the moles of M. Then use moles and mass of M to find its Mr. Use Mass = Mr x Moles and the periodic table.

Reply 2

Hi,
I've drawn out what would be my working
a bit of a mathematical/algebraic approach
sorry it's a bit messy!
what is metal M.png
effectively, fill in what you know, use the ratios you know, use some letters for what you don't know, and solve simultaneously. then calculate Mr of M using this value and what you already know

Reply 3

Thank you so much peeps. Man I actually don't know what I would do without the forum

Reply 4

Original post by suga&kookies
Thank you so much peeps. Man I actually don't know what I would do without the forum

nm
Original post by bl0bf1sh
Hi,
I've drawn out what would be my working
a bit of a mathematical/algebraic approach
sorry it's a bit messy!
what is metal M.png
effectively, fill in what you know, use the ratios you know, use some letters for what you don't know, and solve simultaneously. then calculate Mr of M using this value and what you already know


Original post by TheVirtualPhoton
I suggest first writing an equation to keep track of what’s going on. Work out the mass and moles of Cl in the reaction. Use moles of Cl to get the moles of M. Then use moles and mass of M to find its Mr. Use Mass = Mr x Moles and the periodic table.

Reply 5

Original post by bl0bf1sh
Hi,
I've drawn out what would be my working
a bit of a mathematical/algebraic approach
sorry it's a bit messy!
what is metal M.png
effectively, fill in what you know, use the ratios you know, use some letters for what you don't know, and solve simultaneously. then calculate Mr of M using this value and what you already know


Please avoid giving a full solution. It is against the forum rules. :smile:

Reply 6

Original post by 5hyl33n
Please avoid giving a full solution. It is against the forum rules. :smile:

shut up

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