Thiru01
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Given that 33x^6 - 3(xy)^4 + (3x^2)^3 divided by 6x^2 can be written in the form -10x^p - 1/2x^q y ^r, find the values of p, q and r.

For this question, shouldn't the final expression you get, begin with 10x^4 and not -10x^4?
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davros
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(Original post by Thiru01)
Given that 33x^6 - 3(xy)^4 + (3x^2)^3 divided by 6x^2 can be written in the form -10x^p - 1/2x^q y ^r, find the values of p, q and r.

For this question, shouldn't the final expression you get, begin with 10x^4 and not -10x^4?
looks like it, unless there's a typo somewhere

Do you have an image of the original question?
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Thiru01
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(Original post by davros)
looks like it, unless there's a typo somewhere

Do you have an image of the original question?
Yep, I got it from a textbook so it could be a typo, thanks for the help!
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mqb2766
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(Original post by Thiru01)
Yep, I got it from a textbook so it could be a typo, thanks for the help!
The first one looks like a hyphen rather than a subtraction sign. Dodgy typesetting at best.
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Ice.Log
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So first you expand out 3(xy)^4 to give 3x^4y^4 and expand (3x^2)^3 to give 27x^6. Now you've got
(33x^6-3x^4y^4+27x^6)/6x^2. You can add 33x^6 and 27x^6 to get 60x^6, simplifying it to
(60x^6-3x^4y^4)/6x^2. Divide everything by 6x^2 to get
10x^4-1/2x^2y^4 as your solution.
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